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Vitek1552 [10]
3 years ago
13

Assume the price of gasoline doubles tonight and remains at that price the next two years. The price elasticity of demand for ga

soline measured tomorrow will be ______ when compared with the price elasticity of demand for gasoline measured two years from now.
Physics
1 answer:
Serggg [28]3 years ago
5 0

Answer:

more inelastic

Explanation:

Assume the price of gasoline doubles tonight and remains at that price for the next two years. The price elasticity of demand for gasoline measured tomorrow will be <u>more inelastic</u> when compared with the price elasticity of demand for gasoline measured two years from now.

Inelastic refers to the static quantity of a good or service when its price changes.

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Two people were pulling this thing with 560 Newton. Now they are using a rope with 50°. How much Newton would they need to pull
Brums [2.3K]

Answer:

10 N

Explanation:

While many people would like to simply add the forces from each end to get a total force, this is fundamentally incorrect.

MIGHT BE TOTALLY WRONG

4 0
3 years ago
Explain how information is transferred from one telephone to another one when both the telephones are mobile phones 
Setler79 [48]
Satellites transfer all our information from ken mobile device to another
5 0
3 years ago
Read 2 more answers
Why do fields store potential energy? an object in the field has charge, fields don’t store potential energy, stationary objects
SpyIntel [72]

Answer:

Hey

Your answer would be:

stationary objects within the field will move when realesed.

The reason why is because fields store potential energy as you know. when something is stationary it has potential, but when it is released that potential energy turns into kinetic energy.

this made me think of a funny joke:

A man was about to jump off of the Empire State Building when a physicist from below yield, Wait don't! you have so much potential!

lol always cracks me up.

6 0
3 years ago
A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.
Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V  = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver  will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length  n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

8 0
3 years ago
An 30-turn coil has square loops measuring 0.341 m along a side and a resistance of 3.61 Ω. It is placed in a magnetic field tha
Verdich [7]

Answer:

Thus, the induced current in the coil at t =1.73s is 9.98 A.

Explanation:

Faraday's law says

$\varepsilon = N \frac{d \Phi_B}{dt} $

where N is the number of turns and \Phi_B is the magnetic flux through the square coil:

Now,

N = 30

\theta = 37.5^o

A = (0.341m)^2= 0.11623m^2

B = 1.45t^3;

therefore,

$\varepsilon = N \frac{d \Phi_B}{dt}  = N\frac{d ( BA\:cos(\theta))}{dt}  = 30*\frac{d ( (1.45t^2)(0.1163)\:cos(37.5^o))}{dt}$

=30*(0.1163)\:cos(37.5^o)*1.45*\dfrac{d ( t^3)}{dt}  = 12.04t^2

\boxed{\varepsilon = 12.04t^2}

is the emf induced in the coil.

Now, the loop is connected to R = 3.61\Omega resistance; therefore, at t = 1.73s

\varepsilon = RI = 12.04t^2

RI = 12.04(1.73)^2

RI = 36.03

I = \dfrac{36.03}{3.61\Omega }

\boxed{I = 9.98A }

Thus, the current in the coil at t =1.73s is 9.98 A.

8 0
4 years ago
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