<span>GPE= mgh = 0.1 kg * 9.8 m/s^2 * 12.5m = 12.25 J</span>
Answer:
Technician A
Explanation:
If Technician B was correct, and the master cylinder is defective - then no braking action would occur.
This is not true however, as some breaking action eventually occurs, meaning it must be out of adjustment.
Answer:
F = 1.24*10^4 N
Explanation:
Given
Depth of the ship, h = 25 m
Density of water, ρ = 1.03*10^3 kg/m³
Diameter of the hatch, d = 0.25 m
Pressure of air, P(air) = 1 atm
Pressure of water =
P(w) = ρgh
P(w) = 1.03*10^3 * 9.8 * 25
P(w) = 2.52*10^5 N/m²
P(net) = P(w) + P(air) - P(air)
P(net) = P(w)
P(net) = 2.52*10^5 N/m²
Remember,
Pressure = Force / Area, so
Force = Area * Pressure
Area = πr² = πd²/4
Area = 3.142 * 0.25²/4
Area = 3.142 * 0.015625
Area = 0.0491 m²
Force = 0.0491 * 2.52*10^5
F = 12373 N
F = 1.24*10^4 N
Answer:
total surface area is 432
Explanation:
Given data
base = 6
diagonals = 8
altitude = 12
to find out
total surface area
solution
we know total surface area of prism is
total surface area = lateral surface area + 2base area ..............1
so
first we calculate base perimeter i.e = 2 length + 2 width
so perimeter = 2(8) + 2(6) = 25
and area = length * width = 8*6 = 48
so lateral surface area is perimeter * height i.e
lateral surface area = 28* 12
lateral surface area = 336
put this value in equation 1 we get
total surface area = lateral surface area + 2base area
total surface area = 336 + 2(48)
total surface area is 432
