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Vesna [10]
3 years ago
7

Students are using a mallet to hit a drum. The diagram below shows this action.

Physics
2 answers:
ahrayia [7]3 years ago
4 0
S o is o a one I. Isn’t I e one
alexandr402 [8]3 years ago
4 0

Answer:

A

Explanation:

i think

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39 g aluminum spoon (specific heat 0.904 J/g·°C) at 24°C is placed in 166 mL (166 g) of coffee at 83°C and the temperature of th
tatuchka [14]

<u>Answer:</u> The final temperature of the solution is 80.14^oC

<u>Explanation:</u>

The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, \text{heat}_{absorbed}=\text{heat}_{released}

To calculate the amount of heat released or absorbed, we use the equation:  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

Also,

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]    ..........(1)

where,

q = heat absorbed or released

m_1 = mass of aluminium = 39 g

m_2 = mass of coffee = 166 g

T_{final} = final temperature = ?

T_1 = temperature of aluminium = 24^oC

T_2 = temperature of coffee = 83^oC

c_1 = specific heat of aluminium = 0.904J/g^oC

c_2 = specific heat of coffee= 4.1801J/g^oC

Putting all the values in equation 1, we get:

39\times 0.904\times (T_{final}-24)=-[166\times 4.1801\times (T_{final}-83)]

T_{final}=80.14^oC

Hence, the final temperature of the solution is 80.14^oC

4 0
3 years ago
PLEASE HELP!!! WOULD REALLY APPRECIATE!
Eva8 [605]

Answer:

a. slope=rise/run

rise=0.02

run=-2

determined using the point (3,0.08) and (1,0.1) on the graph

slope=0.02/-2

= -0.01 or -1/100

b.area= area of trapizoid+ rectangle

((0.07+0.11)÷2)×4+1×0.07

0.36+0.07

=0.43$

c. the area represent the total cost after 5 hours

PLEASE MARK BRAINLIEST

3 0
2 years ago
The charge that passes a cross-sectional area A=10-4 m2 varies with time according
Anarel [89]

Answer:

Current = dQ/dt

or I = dQ/dt

Where I represents current.

Which is the rate of flow of charge.

Q=4 + 2t + t²

dQ/dt = 2 + 2t --- This is the relation that gives the instantaneous current.

At time t=2sec

dQ/dt = I = 2 + 2t

= 2 + 2(2)

=2 + 4

= 6A.

6 0
3 years ago
Imagine that a bowling ball needs to be lifted 1.5 meters, and its gravitational potential energy is 90 joules. How much does th
Vikki [24]

Answer: 6.12 kg

Explanation:

Since Mass of ball = ? (let the unknown value be Z)

Acceleration due to gravity, g= 9.8m/s^2

Height, h = 1.5 metres

Gravitational potential energy GPE = 90J

Gravitational potential energy depends on the weight of the ball, the action of gravity and height.

Thus, GPE = Mass m x Acceleration due to gravity g x Height h

90J = Z x 9.8m/s^2 x 1.5m

90 = Z x 14.7

Z = 90/14.7

Z = 6.12 kg

Thus, the bowling ball weigh 6.12 kilograms

8 0
3 years ago
Why is sun the only star that can be seen during day time​
hoa [83]

Explanation:

i think the sun is near the earth that's why we see the sun during the day and the moon is behind the sun so when it is in the night the moon will remove in front the sun and there will be night I hope it will help you

7 0
3 years ago
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