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Dmitry_Shevchenko [17]
3 years ago
14

I need so much help 50 points!!!!!!complete the graph

Physics
1 answer:
motikmotik3 years ago
6 0

<u>First Symbol </u>: Cobalt (Co)

Its Group Number - 9

Its Period Number - 4

Its Family Name - Transition Metal

<u>Second Symbol</u> : Silicon (Si)

Its Group Number - 14

Its Period Number - 2

Its Family Name - Semiconductor

<u>Third Symbol</u> : Astatine (At)

Its Group Number - 17

Its Period Number - 6

Its Family Name - Halogen

<u>Fourth Symbol </u>: Magnesium (Mg)

Its Group Number - 2

Its Period Number - 3

Its Family Name - Alkaline Earth Metal

<u>Fifth Symbol</u> : Xenon (Xe)

Its Group Number - 18

Its Period Number - 5

Its Family Name - Noble Gas

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Serjik [45]
If they fit and have good durability
4 0
4 years ago
The paper dielectric in a paper-and-foil capacitor is 0.0800 mm thick. Its dielectric constant is 2.50, and its dielectric stren
jeka94

Answer:

a) 0.723 m²

b) 2000V

Explanation:

Given that

Thickness of the capacitor, d = 0.08*10^-3 m

Dielectric constant of the capacitor, k = 2.5

Dielectric strength of the capacitor, E = 50*10^6

Capacitance of the capacitor, C = 0.2*10^-6

Permittivity of free space, E• = 8.85*10^-12

a)

The area, A is given by the formula

A = (C * d) / (k * E•)

A = (0.2*10^-6 * 0.08*10^-3) / (2.5 * 8.85*10^-12)

A = 1.6*10^-11 / 2.213*10^-11

A = 0.723 m²

b)

Potencial difference, V is given by the formula

V = E * d

V = 1/2 * 50*10^6 * 0.08*10^-3

V = 1/2 * 4000

V = 2000 V

8 0
4 years ago
Downward force of magnitude 5 N isexerted on the book by the force ofthetablegravityinertia .
mylen [45]

Downward force of magnitude 5 N is exerted on the book by the force of <em>gravity</em>.  We call that the "weight" of the book.

At the same time, upward force of 5 N is exerted on the book by the table.  This one is called the "normal force".

Since the vertical forces on the book are 'balanced' (add up to zero), the book just lays there on the table, and does not accelerate.  

4 0
3 years ago
PLSSSSSSSS SOMEONE HELP ME WITH THIS ONE!!
zloy xaker [14]

Answer:

D

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At the other end of the spectrum toward red, the wavelengths are longer and have lower energy.

8 0
3 years ago
A projectile is launched with an initial velocity of (40 m/s), at an angle of (30°) above
zlopas [31]

Answer:

330.5  m

Explanation:

In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .

The maximum height will be calculated as;

h=\frac{v^2_isin^2\alpha }{2g}

where ∝ is the angle of launch = 30°

vi= initial launch velocity = 40 m/s

g= 10 m/s²

h= 40²*sin²40° / 2*10

h={1600*0.4132 }/ 20

h= 661.1/2 = 330.5  m

8 0
3 years ago
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