Oxygen has<span> a higher electro negativity that then Sulfur, so Sulfur </span>will<span> " lose" electrons to Oxygen and that </span>is<span> the electrons </span>will be<span> pulled closer to the Oxygen causing, for oxygen to </span>have a negative<span> charge and the Sulfur to </span>have<span> a positive charge</span>
Answer:
E
Explanation:
Using Coulomb's law equation
Force of the charge = k qQ /d²
and E = F/ q
substitute for F
E = ( K Qq/ d² ) / q
q cancel q
E = KQ / d²
so twice the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²
With the given values of 
, we have
Try dealing with the powers of 10 first: On the right, we have
Meanwhile, the other values on the right reduce to
Then taking units into account, we end up with the equation
Now we solve for 
:
or, if taking significant digits into account,
Vi = 15 m/s
t = 2 s
a = 9.8 m/s^2
y = ?
The kinematic equation that has all of our variables is d = Vi*t + 0.5*a*t^2
y = 15*2 + 0.5*9.8*2^2 = 49.6 m
