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Ipatiy [6.2K]
3 years ago
10

A 5.00 kg mass is attached to a spring on a horizontal frictionless surface. The elastic constant of the spring is 37.9 N/m. If

the mass is 39.0 cm right of the equilibrium point and moving at speed 7.4 m/s, find the total mechanical energy
Physics
1 answer:
Fynjy0 [20]3 years ago
6 0

45.6 i think i'm not sure pls double check

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A 40-W lightbulb is 1.7 m from a screen. What is the intensity of light incident on the screen? Assume that a lightbulb emits ra
Sonja [21]

Answer:

Intensity, I=1.101\ W/m^2

Explanation:

Power of the light bulb, P  = 40 W

Distance from screen, r = 1.7 m

Let I is the intensity of light incident on the screen. The power acting per unit area is called the intensity of the light. Its formula is given by :

I=\dfrac{P}{A}

I=\dfrac{P}{4\pi r^2}

I=\dfrac{40\ W}{4\pi (1.7\ m)^2}

I=1.101\ W/m^2

So, the intensity of light is 1.101\ W/m^2.

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A tree is 24 feet 8 inches tall. What is its height in meters?
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A ping-pong ball is shot straight north from a popgun at 4.0 m/s. The wind is blowing to the west at 3.0 m/s. What is the actual
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Actual velocity of the ping-pong ball= 5 m/s

Explanation:

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4 years ago
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