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Aloiza [94]
4 years ago
9

If hydrogen-1 has 1 proton how many protons does hydrogen-2 have?

Chemistry
1 answer:
Vikentia [17]4 years ago
5 0
Number of protons remain the same however number of neutron increases. <span />
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What are some examples of some monotonic ions found in the body and how do they affect the body? Please help, anything will help
Luba_88 [7]
Atoms are electrically neutral because the number of protons, which carry a 1+ charge, in the nucleus of an atom is equal to the number of electrons, which carry a 1- charge, in the atom. The result is that the total positive charge of the protons cancels out the total negative charge of the electrons so that the net charge of the atom is zero. Most atoms, however, can either gain or lose electrons; when they do so, the number of electrons becomes different from the number of protons in the nucleus. The resulting charged species is called an ion.

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4 years ago
The specific heat of a substance which absorbs 7.5 x 10^3 J of
Veronika [31]

Answer:

9.4 x 10^-4 J/g°C

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3 years ago
A compound contains 36.48% Na, 25.41% S, and 38.11% O. Find it’s empirical formula
MAXImum [283]

Answer:

we can use 100g of compounds as the basis.

Explanation:

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2 years ago
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3 0
3 years ago
You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add
Nookie1986 [14]

your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

molarity=mol soluteL soln

5 0
3 years ago
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