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3 years ago

If hydrogen-1 has 1 proton how many protons does hydrogen-2 have?

Chemistry

1 answer:

Vikentia [17]3 years ago

5 0

Number of protons remain the same however number of neutron increases. <span />

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7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.

Effectus [21]

<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

The units used to measure length include;

Kilometer(km)

Hectometer (Hm)

Decameter (dkm)

Meter(m)

Decimeter (dm)

Centimeter (cm)

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

7 0

2 years ago

Read 2 more answers

Electrolytic cells use electricity to cause a nonspontaneous redox reaction to occur. An electrolytic cell is constructed using

Fittoniya [83]

Answer:

At anode - ${Br_2}_{(l)}$

At cathode - ${H_2}_{(g)}$

Explanation:

Electrolysis of NaBr:

Water will exist as:

$H_2O\rightleftharpoons H^++OH^-$

The salt, NaBr will dissociate as:

$NaBr\rightarrow Na^++Br^-$

At the anode, oxidation takes place, as shown below.

${Br^-}_{(aq)}\rightarrow {Br_2}_{(l)}+2e^-$

At the cathode, reduction takes place, as shown below.

$2{H^+}_{(aq)}+2e^-\rightarrow {H_2}_{(g)}$

4 0

2 years ago

The movement of broken down pieces of rock from one place to another is called

Dvinal [7]

Answer:

The answer I believe is B. Erosion

Explanation:

Just sounds better than all the other choices.

7 0

2 years ago

Read 2 more answers

. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r

Tom [10]

Answer : The energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

Explanation : Given,

Wavelength = $435.8nm=435.8\times 10^{-9}m$

conversion used : $1nm=10^{-9}m$

Formula used :

$E=h\times \nu$

As, $\nu=\frac{c}{\lambda}$

So, $E=h\times \frac{c}{\lambda}$

where,

$\nu$ = frequency

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength = $435.8\times 10^{-9}m$

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}$

$E=4.56\times 10^{-19}J$

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

3 0

3 years ago

Which statement describes a chemical property that can be used to distinguish between compound A and compound B?

AURORKA [14]

Answer:

Explanation:

(4) A does not burn in air, and B does burn in air is your answer. Flammability is a chemical property while the rest of these are physical properties.

Still stuck? Get 1-on-1 help from an expert tutor now.

7 0

2 years ago