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Orlov [11]
4 years ago
10

A rectangular coil of wire (a = 22.0 cm, b = 46.0 cm) containing a single turn is placed in a uniform 4.60 T magnetic field, as

the drawing shows. The current in the loop is 10.0 A. Determine the magnitude of the magnetic force on the bottom side of the loop.

Physics
1 answer:
frez [133]4 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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A basketball player throws the ball at a 47 angle above the horizontal to a hoop which is located a horizontal distance L = 5.0
FromTheMoon [43]

Answer:

v_0 =1.71

Explanation:

the parabolic movment is described by the following equation:

y = tan(a)x-\frac{1}{2v_0^2(cos(a))^2}gx^2

where y is the height of the ball, a is the angle of launch, v_0 the initial velocity, g the gravity and x is the horizontal distance of the ball.

So, if we want that the ball reach the hood, we will replace values on the equation as:

0.8 = tan(47)(5)-\frac{1}{2v_0^2(cos(47))^2}(9.8)(5)^2

Finally, solving for v_0, we get:

v_0=\sqrt{\frac{-9.8(5)^2}{(0.8-tan(47)(5))2cos^2(47)}}

v_0 =1.71

4 0
4 years ago
If the mass of the earth and all objects on it were suddenly doubled, then the ________
krok68 [10]

Answer:

The force of universal gravitation between earth and all objects in it will be quadrupled

Explanation:

Newtons law of universal gravitation tell us the force of attraction between two bodies on the earth surface . This force is directly proportional to the product of the masses of the bodies and inversely proportional to their distance apart.

f is directly proportional to m1*m2

doubling these masses will be 2m1*2m2 = 4m1m2

if mas of earth is Me and mass of all objects is Mo

the f is proportional to Me*Mo

doubling the masses of the earth and all objects we have, 2Me*2Mo= 4MeMo

This means that doubling the masses of the earth and all objects on it will cause the force of gravitational attraction to be quadrupled.

3 0
3 years ago
What determines if a star becomes a dwarf, neutron star or a black hole?
faust18 [17]
I'm pretty sure it's the neutron star.
3 0
3 years ago
At a certain location, the horizontal component of the earth's magnetic field is 2.5 × 10−5 T, due north. A proton moves eastwar
Bogdan [553]

Answer:

  v = 4.10 10⁻³ m / s

Explanation:

For this exercise we will use Newton's second law where the force is magnetic

       F -W = m a

As the field is directed to the north and the proton to the east, using the rule of the right hand the force is vertical upwards, the force balances the weight the acceleration is zero

      F = W

      q v B = m g

Let's calculate the speed

      v = m g / (q B)

      v = 1,673 10⁻²⁷ 9.8 / (1.6 10⁻¹⁹ 2.5 10⁻⁵)

       v = 4.10 10⁻³ m / s

7 0
4 years ago
How to make a force field for your house
Lelu [443]
That is not yet possible. that technology has not yet been invented.
6 0
3 years ago
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