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Orlov [11]
3 years ago
10

A rectangular coil of wire (a = 22.0 cm, b = 46.0 cm) containing a single turn is placed in a uniform 4.60 T magnetic field, as

the drawing shows. The current in the loop is 10.0 A. Determine the magnitude of the magnetic force on the bottom side of the loop.

Physics
1 answer:
frez [133]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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A train increases its speed steadily from 10 m/s to 20 m/s in
rewona [7]

Answer:

15m/s

Explanation:

add the two speeds and divide by 2

10+20=30

30/2=15

3 0
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6th grade science !!!!!!!!!!!!!!!​
posledela

Answer:

71

Explanation:

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An 75-kg hiker climbs to the summit of Mount Mitchell in western North Carolina. During one 2.0-h period, the climber's vertical
Ostrovityanka [42]

Answer:

The change in gravitational potential energy of the climber-Earth system is  \Delta  PE  = 396900 \ J

Explanation:

From the question we are told that

    The mass of the hiker is  m = 75 \ kg

    The time  taken is  T  =  2 \ hr =  2 *  3600 =  7200 \ s

    The  vertical elevation after time  T is  H = 540 \ m

   

The  change  in gravitational potential is  mathematically represented as

         \Delta  PE  =  mgH

here g is the acceleration due to gravity with value  g =  9.8 \ m/s^2  

     substituting values  

        \Delta  PE  =  75  *  9.8  *  540

       \Delta  PE  = 396900 \ J

3 0
3 years ago
A piece of wood on top of an ocean wave stays in the same location, only moving up and down as the wave passes. It is energy tha
Ierofanga [76]

Answer:

Hey

Yes, this is true.

As some people have it wrong, waves in the water (ocean) are not waves of moving water, rather the wave is moving through the water. A wave is a disturbance of a medium not the meduim moving.

8 0
3 years ago
A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy
Vsevolod [243]

Answer:

v = 4.2 \ m/s

Explanation:

Given data:

Mass of the paper clip, m = 1.5 \ g = 0.0015 \ kg

Kinetic energy, K = 0.013 \ \rm J

Let the velocity of the paper clip when it is thrown be <em>v</em>.

Thus,

K = \frac{1}{2}mv^{2}

0.013 = 0.5 \times 0.0015 \times v^{2}

\Rightarrow \ v = 4.16 \ m/s

v = 4.2 \ m/s.  (rounding to nearest tenth)

3 0
3 years ago
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