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trapecia [35]
4 years ago
9

A string has a mass of 12.3 g. The string is stretched with a force of 8.67 N, giving it a length of 1.81 m. Then, the string vi

brates transversely at precisely the frequency that corresponds to its fourth normal mode; that is, at its fourth harmonic. What is the wavelength of the standing wave created in the string?
Physics
1 answer:
Marina CMI [18]4 years ago
4 0

Answer:

λ = 0.905m

Explanation:

TThe wavelength (λ) only depends on the harmonic (n) and the length of the string (L):

λ = 2L/n

λ = 2*1.81m /4

λ = 0.905m

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Deadpool is doing a superhero landing from a 21 meter tall building what would his velocity be right before he hits the ground?
Morgarella [4.7K]

Answer:

I think he would be dead poggers

Explanation:

4 0
3 years ago
Charge A and charge B are 3.00 m apart, and charge A is +1.44 C and charge B is +3.10 C. Charge C is located between them at a c
Sidana [21]

Answer:

the distance from charge A to C is r₁₃= 1.216 m

Explanation:

following Coulomb's law , the force exerted by 2 point charges between themselves is:

F= k*q₁*q₂/r₁₂² , where q is charge , r is distance and 1 and 2 represents the charge A and charge B respectively , k=constant

since C ( denoted as 3) is at equilibrium

F₁₃=F₂₃

k*q₁*q₃/r₁₃²=k*q₂*q₃/r₂₃²

q₁/r₁₃²=q₂/r₂₃²

r₁₃²/q₁=r₂₃²/q₂

r₂₃=r₁₃*√(q₂/q₁)

since C is at rest and is co linear with A and B ( otherwise it would receive a net force in either vertical or horizontal direction) , we have

r₁₃+r₂₃=d=r₁₂

r₁₃+r₁₃*√(q₂/q₁)=d

r₁₃*(1+√(q₂/q₁))=d

r₁₃=d/(1+√(q₂/q₁))

replacing values

r₁₃=d/(1+√(q₂/q₁)) = 3.00 m/(1+√(3.10 C/1.44 C)) = 1.216 m

thus the distance from charge A to C is r₁₃= 1.216 m

7 0
3 years ago
A bus travels east for 3 km the north for 4 km what is its final displacement
lesya [120]
Im about to the math for this right now.
8 0
3 years ago
A girl throws a marshmallow that lands in her friend’s mouth 2 m away. The girl threw the marshmallow at an angle of 30 degrees.
natima [27]

She threw the marshmallow at a speed of around 4.76 m/s.The formula for the horizontal range gives the velocity.

<h3>What is projectile motion?</h3>

The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.

The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.

Given data;

The marshmallow was thrown at a distance of 2 meters

Range,R =  3 m

Initial velocity,u

The angle at which the marshmallow was thrown,θ = 30°

The acceleration due to gravity,g = 9.81 m/s²

The projectile's motion is divided into two parts: horizontal and vertical motion.

\rm R = \frac{u^2sin2 \theta }{g} \\\\ \rm R  = \frac{u^2sin2 \times (30) }{9.81} \\\\ u^2=\frac{2 \times 9.81 }{sin 60^0} \\\\ u^2=22.66 \\\\ u=4.76 \ m/sec

Hence, she throws the marshmallow at a speed of 4.76 m/sec.

To learn more about the projectile motion refer to the link;

brainly.com/question/11049671

#SPJ1

4 0
2 years ago
What is the source of all magnetism?
ivanzaharov [21]
The answer is electric current
3 0
3 years ago
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