A string has a mass of 12.3 g. The string is stretched with a force of 8.67 N, giving it a length of 1.81 m. Then, the string vi
1 answer:
You might be interested in
Answer:
c. 2 MeV.
Explanation:
The computation of the binding energy is shown below
= 2 MeV
As 1 MeV = (1 u) c^2
hence, the binding energy is 2 MeV
Therefore the correct option is c.
We simply applied the above formula so that the correct binding energy could come
And, the same is to be considered
Mary and her younger brother Alex decide to ride the carousel at the State Fair, Mary's and Alex's angular speed M and tangential speed vM is mathematically given as
Mary's and Alex's angular speed=1.43
Tangential speed mary=3.22 m/s
Tangential speed alex =2.260m/s
<h3>What is Mary's and Alex's angular speed M and tangential speed vM?</h3>Generally, the equation for angular speed is mathematically given as
w = 1.61 rev/see 3.9
Centripetal acc mary = v^2/r
Centripetal acc mary = w^2r
Centripetal acc mary = w^2x 2m
Centripetal acc. of Alex = w²x L.u
Therefore
Hence
tang. speed V=Wr
tang. speed of mary = 1.61x2 = 3.22 m/s
tang. speed of Alex: 1.61X1·4 =2.260m/s
Read more about Speed
#SPJ1
Answer:
Explanation:
<u>Given:</u>
- Mass,
- Velocity,
where,
are the uncertainties in mass and velocity respectively.
The kinetic energy is given by
The uncertainty in kinetic energy is given as: