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Alik [6]
3 years ago
8

A disk is uniformly accelerated from rest with angular acceleration α. The magnitude of the linear acceleration of a point on th

e rim of the disk (a) grows with the time t as ________ for (αt2) << 1.
Physics
1 answer:
solniwko [45]3 years ago
4 0

Answer:

a = R\alpha\sqrt{1 + \alpha^2t^4}

Explanation:

As we know that the acceleration of a point on the rim of the disc is in two directions

1) tangential acceleration which is given as

a_t = R\alpha

2) Centripetal acceleration

a_c = \omega^2 R

here we know that

\omega = \alpha t

a_c = (\alpha t)^2 R

now we know that net linear acceleration is given as

a = \sqrt{a_c^2 + a_t^2}

so we have

a = \sqrt{R^2\alpha^2 + R^2(\alpha t)^4}

a = R\alpha\sqrt{1 + \alpha^2t^4}

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