The instrument is a Geiger counter and is used to measure radioactive level around people's bodies.
Answer:
a) 200A
b) 10.2V
c) 2.04kW
d)
I=80A
V=4.08V
P=0.326kW
Explanation:
Here we have a circuit of one power source and two resistors in series, the first question is asking for the current, so according to Ohm's Law:

Where R is the equivalent resistance of the resistors in series
![R=0.0510+0.0090=0.0600[ohm]](https://tex.z-dn.net/?f=R%3D0.0510%2B0.0090%3D0.0600%5Bohm%5D)

To calculate the voltage dropped by the motor we have to apply the voltage divider rule:

The power dissipated supplied to the motor is given by:

now solving adding a 0.0900 ohm resistor:



Answer:
Technician A
Explanation:
It is seen that a tire pressure will increase or decrease 1 psi for each
change in temperature.
For Technician B vehicle pressure should not be adjusted after tire has been warmed as the warm air may increase the pressure but it will be auto adjusted as the temperature falls to normal .