A negative charge is at rest at the origin of an axis system. Location x is at coordinate point (2m,3m) while location y is at (
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Answer:
The kinetic energy is
Explanation:
From the question we are told that
The radius of the orbit is
The gravitational force is
The kinetic energy of the satellite is mathematically represented as
where v is the speed of the satellite which is mathematically represented as
=>
substituting this into the equation
Now the gravitational force of the planet is mathematically represented as
Where M is the mass of the planet and m is the mass of the satellite
Now looking at the formula for KE we see that we can represent it as
=>
substituting values
Answer:
Explanation:
The magnitude of the net force exerted on q is known, we have the values and positions for and q. So, making use of coulomb's law, we can calculate the magnitude of the force exerted by
on q. Then we can know the magnitude of the force exerted by
about q, finally this will allow us to know the magnitude of
exerts a force on q in +y direction, and
exerts a force on q in -y direction.
The net force on q is:
Rewriting for :
The weight of the meterstick is:
and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance
from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
from which we find the value of d2:
So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.
and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance
from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
from which we find the value of d2:
So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.