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Georgia [21]
3 years ago
13

What is the potential energy of a 5kg rock that is 7m high on a hill

Physics
1 answer:
Goryan [66]3 years ago
4 0

Explanation:

Gravitational potential energy = mgh = (5)(9.81)(7) = 343.35J.

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1) If you release a rubber band that had 10 units of elastic energy, 12 units of movement energy cannot be produced. Why not?
Mila [183]

Answer:

press dat crown for meh

Explanation:

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3 years ago
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What is a disadvantage associated with many renewable or alternative energy sources
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Its pretty expensive and can't be replaced immediately and some source like nuclear energy produces nuclear waste which produce radioisotope that is harmful for all living beings
5 0
4 years ago
A train is moving along a track with constant speed v1 relative to the ground. A person on the train holds a ball of mass m and
scoundrel [369]

Answer:

(a)0.5m(2v1v2+v2^{2})\\(b)0.5m(v2^{2}-v1^{2})\\(c)0.5m(2v1v2+v2^{2})\\(d)0.5m(v2^{2}-v1^{2})

Explanation:

velocity of ball in train reference = v2

velocity of ball in earth reference = v1+v2

(a)

Kinetic energy is given by 0.5mv^{2} where m and v are the mass and velocity of object respectively.

Change in kinetic energy is given by subtracting initial kinetic energy from the final kinetic energy. In this case

Initial kinetic energy= 0.5mv1^{2}

Final kinetic energy= 0.5m (v1+v2)^{2}=0.5m(v1^{2}+2v1v2+v2^{2})

Change in kinetic energy=0.5m (v1+v2)^{2}-0.5mv1^{2}=0.5m((v1+v2)^{2})-v1^{2}=0.5m(2v1v2+v2^{2}

(b)

Change in velocity in train reference will be

Initial kinetic energy= 0.5mv1^{2}

Final kinetic energy= 0.5mv2^{2}

Change in kinetic energy=0.5m(v2^{2}-v1^{2})

(c)

Work done, W = change in kinetic energy=0.5m (v1+v2)^{2}-0.5mv1^{2}=0.5m((v1+v2)^{2})-v1^{2}=0.5m(2v1v2+v2^{2}

(d)

Work done, W = change in kinetic energy=0.5m(v2^{2}-v1^{2})

4 0
3 years ago
Select the correct answer. An object has one force acting on it. It is a 33-newton force pointing downward. To create a net forc
kiruha [24]

Answer:

33 Newton upwards to get a net force of zero.

4 0
3 years ago
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What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity o
stira [4]

The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.

<h3>What is the force exerted on the charge?</h3>

Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.

when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.

Mathematically the force exerted on the charge will be

F=qvBsinα

F= force acting on the charge

v = velocity of charge

q = charge

F=qvBsinα

F=2.5×10⁻⁶×5.0×10³×3.0×10²

F=37.5 N

Hence The force acting on the charge will be 3.75 N.

To learn more about the force acting on charge refer to ;

brainly.com/question/451411

F = q V B sinα

Where F is the force applied to a moving charge.

V = charge velocity

q stands for charge.

α = angle between V and B directions

As a result, the moving charge is subjected to a force of 3.75 Newton.

3 0
2 years ago
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