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3 years ago

Does translation change a shapes orientation

Mathematics

2 answers:

cluponka [151]3 years ago

8 0

No it just moves it over

lara [203]3 years ago

6 0

Answer:

Step-by-step explanation:

Translation only moves a shape from one spot to another.

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5. It took Kiara 35.25 minutes to finish her chores on Saturday, while it took her brother Derek

cestrela7 [59]

Kiara I hope that helps

7 0

3 years ago

What is the expasion of (2x + 3)^3 ?

Marianna [84]

Answer:

(2x + 3)3

Step-by-step explanation:

Simplify: (2x+3)(3)

Answer: (2x + 3)3

<em><u>Hope this helps.</u></em>

6 0

3 years ago

Please help Find the value of x

exis [7]

Answer:

Value of x is 2

Step-by-step explanation:

Given

BD = 6

DA = 4

BE = $x+1$

EC = x

Also segment DE is parallel to segment AC

∴ By using Midpoint theorem which states

$\frac{BD}{DA}\cong \frac{BE}{EC}$

Putting the given data in above equation we get

$\frac{6}{4}=\frac{x+1}{x}\\6x=4(x+1)\\6x =4x+4\\6x-4x =4\\2x=4\\x= \frac{4}{2}\\x=2$

6 0

3 years ago

Evaluate the double integral. . ∫∫ y sqrt(x^2-y^2) dA, R={(x,y)|0≤y≤x, 0≤x≤1}. R. . Please explain

polet [3.4K]

First we will evaluate: ( substitution: u = x² - y², du = - 2 y dy )
$\int\limits^x_0 {y \sqrt{ x^{2} - y^{2} } } \, dy= \\ \frac{-1}{2} \int\limits^x_0 { u^{1/2} } \, du =$
= $\frac{-1}{3} \sqrt{ (x^{2} - y^{2} ) ^{3} }$ ( than plug in x and 0 )
= $- \frac{1}{3} ( \sqrt{( x^{2} - x^{2}) ^{3} } - \sqrt{ (x^{2} -0 ^{2} ) ^{3} }$ =
= 1/3 x³ ( then another integration )
$1/3\int\limits^1_0 { x^{3} } \, dx = 1/3 ( x^{4}/4)}= 1/3 ( 1 ^{4}/4 - 0^{4} /4 )$
= 1/3 * 1/4 = 1/12

4 0

3 years ago

The Sine Function

Snezhnost [94]

Answer:

B. Graph B

Step-by-step explanation:

I calculated it logically

3 0

3 years ago