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Brilliant_brown [7]
4 years ago
9

Which compounds are acting like Brønsted-Lowry acids in the following acid-base equilibrium?

Chemistry
2 answers:
Vadim26 [7]4 years ago
4 0

Answer:

The compounds HCO₃⁻ and OH⁻ are acting like a <em>Brønsted-Lowry base and the compounds H₂C0</em><em>₃</em><em> H₂0 are acting like a Brønsted-Lowry acid.</em>

Explanation:

According to the <em>Brønsted-Lowry theory</em> an acid is any  species capable of donating a proton (H⁺) and a base is any species capable of accepting a proton (H⁺)

The conjugate base of a <em>Brønsted-Lowry acid</em><em> is the species that is formed after the acid donates its proton and </em><em>the conjugate acid</em><em> of  </em><em>Brønsted-Lowry </em>base is the species that is formed after the base accepts a proton.

For example:

H₂SO₄ + OH⁻ ⇆ HSO₄⁻ + H₂O

In this equilibrium H₂SO₄ is acting like a <em>Brønsted-Lowry acid </em><em>and</em><em> </em>HSO₄⁻ is its conjugate base. Also OH⁻ is acting like a <em>Brønsted-Lowry </em>base and H₂O is its <em>conjugate acid</em>

So, HCO₃⁻ is acting like a <em>Brønsted-Lowry base </em><em>and</em><em> H₂C0</em><em>₃</em> is its conjugate acid. Also H₂O is acting like a <em>Brønsted-Lowry </em>acid and OH⁻ is its <em>conjugate base.</em>

photoshop1234 [79]4 years ago
3 0
HCO₃⁻ + H₂O ----> CO₃²⁻ + H₃O⁺
H₂O + H₂O ----> H₃O⁺ + OH⁻
H₂CO₃ + H₂O ----> HCO₃⁻ + H₃O⁺

:)
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