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bogdanovich [222]
3 years ago
13

Which of the following statements are true? Select all correct responses. Choose all that apply. Choose all that apply. The tota

l momentum of an isolated system is constant. The total momentum of any number of particles is equal to the algebraic sum of the momenta of the individual particles. The vector sum of forces acting on a particle equals the rate of change of velocity of the particle with respect to time. The vector sum of forces acting on a particle equals the rate of change of momentum of the particle with respect to time. The total momentum of any system is constant. The total momentum of any number of particles is equal to the vector sum of the momenta of the individual particles.
Physics
1 answer:
Ne4ueva [31]3 years ago
3 0
<h3><u>Answer</u>;</h3>

-The total momentum of an isolated system is constant.

-The total momentum of any number of particles is equal to the vector sum of the momenta of the individual particles.

-The vector sum of forces acting on a particle equals the rate of change of momentum of the particle with respect to time.

<h3><u>Explanation</u>;</h3>
  • Momentum is a vector quantity, and therefore we need to use vector addition when summing together the momenta of the multiple bodies which make up a system.
  • The vector sum of forces acting on a particle is equivalent to the rate of change of momentum of the particle with respect to time. This is according to the Newton's second Law of motion. In mathematical terms, ֿF = d ֿp/dt, that is F= ma.
  • According to the Law of conservation of Momentum, or a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
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Two parallel 3.0-meter long wires conduct current. The current in the top wire is 12.5 A and flows to the right. The top wire fe
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Complete question:

Two parallel 3.0-meter long wires conduct current. The current in the top wire is 12.5 A and flows to the right. The top wire feels a repulsive force of 2.4 x 10^-4 N created by the interaction of the 12.5 A current and the magnetic field created by the bottom current (I). Find the magnitude and direction of the bottom current, if the distance between the two wires is 40cm.

Answer:

The bottom current is 12.8 A to the right.

Explanation:

Given;

length of the wires, L = 3.0 m

current in the top wire, I₁ = 12.5 A

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distance between the two wires, r = 40 cm = 0.4 m

The repulsive force between the two wires is given by;

F = \frac{\mu_oI_1I_2L}{2\pi r}\\\\I_{2} = \frac{2F\pi r}{\mu_oI_1L}

Where;

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The direction of the bottom current must be in the same direction as the top current since the force between the two wires is repulsive.

I_{2} = \frac{2F\pi r}{\mu_oI_1L}\\\\I_{2} = \frac{2(2.4*10^{-4})(\pi)(0.4)}{(4\pi*10^{-7})(12.5)(3)}\\\\I_{2} = 12.8 \ A

Therefore, the bottom current is 12.8 A to the right.

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