Answer:
396.97°C
Explanation:
Charles' Law explains that at constant volume, the pressure of an ideal gas is directly proportional to its temperature (in Kelvin).
P₁ ∝ T₁
P₁ = kT₁
k = constant of proportionality
(P₁/T₁) = (P₂/T₂)
P₁ = 240.0 kPa
T₁ = Boiling point of water = 100°C = 373.15 K
P₂ = 431.0 kPa
T₂ = ?
(240/373.15) = (431/T₂)
T₂ = (431 × 373.15) ÷ 240
T₂ = 670.12 K
T₂ = 396.97°C
Hope this Helps!!!
<em>Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.</em>
Answer:
Explanation:
a) According to ohm's law
V = IR
V is the supply voltage
R is the resistance
I is the current
Given Resistance = 200ohms
Voltage = 20V
I = V/R
I = 20/200
I = 0.1Amperes
b) Using the ohm's law formula
V= IR
Where voltage = 12volts
Current I = 3A
Resistance R = V/I
R = 12/3
R = 4ohms
c) Power generated by the battery is expressed as P = IV
I = P/V
Given Power = 2Watts
V = 1.5volts
I = 2/1.5
I = 1.33A
d) similarly, power = current I × voltage V
V = P/I
Given P = 90watts
I = 4.5A
V = 90/4.5
V = 20volts
e) Given power = 1.5kW = 1500watts
Voltage = 300volts
I = P/V
I = 1500/300
I = 5A
Jackson sells lemonade for $2 per cup. he paid $20 for supplies to sell 5 cups. What is the domain for this scenario
Answer:
a) 0.64 b) 2.17m/s^2 c) 8.668joules
Explanation:
The block was on the ramp, the ramp was inclined at 20degree. A force of 5N was acting horizontal to the but not parallel to the ramp,
Frictional force = horizontal component of the weight of the block along the ramp + the applied force since the block was just about move
Frictional force = mgsin20o + 5N = 6.71+5N = 11.71
The force of normal = the vertical component of the weight of the block =mgcos20o = 18.44
Coefficient of static friction = 11.71/18.44= 0.64
Remember that g = acceleration due to gravity (9.81m/s^2) and m = mass (2kg)
b) coefficient of kinetic friction = frictional force/ normal force
Fr = 0.4* mgcos 20o = 7.375N
F due to motion = ma = total force - frictional force
Ma = 11.71 - 7.375 = 4.335
a= 4.335/2(mass of the block) = 2.17m/s^2
C) work done = net force *distance = 4.335*2= 8.67Joules
