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zysi [14]
4 years ago
10

A spring is compressed between two objects with unequal masses, m and M, ad held together. The objects are initially at rest on

a horizontal frictionless surface. When released, which of the following is true?
Physics
1 answer:
AlekseyPX4 years ago
5 0

Answer:

Explanation:

The complete question is here.

A spring is compressed between two objects with unequal masses, m and M, held together. The objects are initially at rest on a horizontal friction less surface. When released, which of the following is true?

a) Kinetic energy is same as before being released

b) The total final kinetic energy is zero.

c) The two objects have equal kinetic energy.

d) The speed of one object is equal to the speed of other.

e) The total final momentum of two objects is zero.

So option e) the total final momentum of two objects is zero.

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The tension in a string from which a 4.0 kg object is suspended in an elevator is equal to 44 N. What is the acceleration of the
Ronch [10]

Answer: 1

Explanation:

Given

Tension is the string T=44\ N

mass of object m=4\ kg

Tension is greater than the weight of the object i.e. elevator is moving upward

we can write

\Rightarrow T-mg=ma\\\Rightarrow T=m(g+a)\\\Rightarrow 44=4(10+a)\\\Rightarrow 11=10+a\\\Rightarrow a=1\ m/s^2

8 0
3 years ago
A school bus moves slower and slower. Using what you have learned about forces, explain why the bus moves slower and slower.
MariettaO [177]

Explanation:

the weight of the people inside the bus

4 0
3 years ago
Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di
kirill115 [55]

The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

  • time of fall of the first ball, t = 1 s
  • time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m

The distance traveled by the second ball is calculated as follows;

h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m

Thus, the second ball traveled a greater distance because it spent more time in motion.

Learn more here:brainly.com/question/5868480

3 0
2 years ago
One of the explorers is able to jump a maximum distance of 19.5 m with an initial speed of 2.80 m/s. Find the gravitational acce
BlackZzzverrR [31]

Answer:

0.2 m/s^2

Explanation:

Maximum distance, h = 19.5 m

initial speed, u = 2.80 m/s

final speed, v = 0 m/s

Let the gravitational acceleration is a.

Use third equation of motion

v^{2}=u^{2}-2\times a\times h

0^{2}=2.80^{2}-2\times a\19.5

2\times a\19.5=7.84

a = 0.2 m/s^2

Thus the gravitational acceleration on the exoplanet is 0.2 m/s^2

8 0
3 years ago
You can answer this to get points its not an actual question
larisa86 [58]

Answer:

the electromagnetic pulse

Explanation:

8 0
3 years ago
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