Question

One of the explorers is able to jump a maximum distance of 19.5 m with an initial speed of 2.80 m/s. Find the gravitational acceleration on the surface of the exoplanet

Answer 1

Answer:

0.2 m/s^2

Explanation:

Maximum distance, h = 19.5 m

initial speed, u = 2.80 m/s

final speed, v = 0 m/s

Let the gravitational acceleration is a.

Use third equation of motion

$v^{2}=u^{2}-2\times a\times h$

$0^{2}=2.80^{2}-2\times a\19.5$

$2\times a\19.5=7.84$

a = 0.2 m/s^2

Thus the gravitational acceleration on the exoplanet is 0.2 m/s^2