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igomit [66]
4 years ago
6

Which statement is a correct expression of the Law of Conservation of Mass?

Physics
2 answers:
Mumz [18]4 years ago
8 0

Answer: B. The total mass remains the same during a chemical reaction.

Explanation:I Took The Test.

DiKsa [7]4 years ago
7 0
<span>The correct answer is B. The law of conservation of mass states that the mass of an isolated system is neither created nor destroy by chemical reaction or physical transformation. This means that the mass of subtances in an isolated system remains constant, it can not decrease and it can not increase.</span>
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A 1.15-kg mass oscillates according to the equation x = 0.650 cos(8.40t) where x is in meters and t in seconds. Determine (a) th
zheka24 [161]

Answer:

(a) A = 0.650 m

(b) f = 1.3368 Hz

(c) E = 17.1416 J

(d)  K = 11.8835 J

     U = 5.2581 J

Explanation:

Given

m = 1.15 kg

x = 0.650 cos (8.40t)

(a) the amplitude,

A = 0.650 m

(b) the frequency,

if we know that

ω = 2πf = 8.40    ⇒   f = 8.40 / (2π)

⇒   f = 1.3368 Hz

(c) the total energy,

we use the formula

E = m*ω²*A² / 2

⇒  E = (1.15)(8.40)²(0.650)² / 2

⇒  E = 17.1416 J

(d) the kinetic energy and potential energy when x = 0.360 m.

We use the formulas

K = (1/2)*m*ω²*(A² - x²)       (the kinetic energy)

and

U = (1/2)*m*ω²*x²              (the potential energy)

then

K = (1/2)*(1.15)*(8.40)²*((0.650)² - (0.360)²)

⇒  K = 11.8835 J

U = (1/2)*(1.15)*(8.40)²*(0.360)²

⇒  U = 5.2581 J

4 0
3 years ago
[K1 A2 T1 C1] A golfer strikes a golf ball on level ground.
gregori [183]

Answer:

Explanation:

See the file attached .

b ) Range of projectile

= u²sin2θ / g

= 42² sin32 x 2 / g

= 42² sin64 / 9.8

= 161.8 m

c )

Max height = u² sin²32 / 2 g

= 42² sin²32 / 2x 9.8

= 25.27  m .

6 0
3 years ago
At a pressure of one atmosphere methane boils at −161°C and freezes at −182.5°C. Consider a temperature scale where the boiling
lawyer [7]

Answer:

-421.627906977\^{\circ}M

Explanation:

Absolute zero in the Kelvin scale = -273.15 °C

Temperature difference in the boiling and freezing point

-161-(-182.5)=21.5\ ^{\circ}C

Change in 21.5°C = Change of 100°C in M

1^{\circ}C=\dfrac{100}{21.5}=4.6511627907\ ^{\circ}M

Difference in the Celsius scale

-182.5-(-273.15)=90.65\ ^{\circ}C

Change in 90.65\ ^{\circ}C corresponds to

4.6511627907\times 90.65=421.627906977\ ^{\circ}M

Therefore the absolute zero in the Methane scale is

-421.627906977\ ^{\circ}M

3 0
3 years ago
Susan goes out to exercise. She runs for one hour at a constant speed and velocity. What is the overall net force acting on Susa
kiruha [24]

Option (A ) is correct.

Explanation:

susan is moving with constant velocity, so both the direction and magnitude of the velocity remains same. so the acceleration of susan =0. This is because an object gets accelerated when either the magnitude or direction of the speed changes.

now the force is given by

F= ma

F= force

m= mass

a= acceleration

Here a =0

so F= 0

so the net force on susan is zero.

3 0
3 years ago
Read 2 more answers
Why did she use an red infra lamp
mixas84 [53]
To act as the Sun' was accepted but if you put 'sunlight' alone it was not accepted. The examiner wanted you to state that the infra red radiation was needed to warm up the water.
4 0
3 years ago
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