Let x be the first computer. Let y be the first computer. We know that Work = 1 / Time.
If the work together, work can be done in 30 seconds. Thus, we have:
1/x + 1/y = 1/30
If x will finish in 50 seconds, we need to compute how many seconds y can finish the same work. Thus solving for y, we have the equation below:
1/50 + 1/y = 1/30
1/y = 1/30 - 1/50
1/y = 1/75
The second computer can finish the same work in 75 seconds.
Answer:
The answer is 3/4, simplified
Step-by-step explanation:
Hope this helps
Answer:
+1/5
Step-by-step explanation:
Answer:
3^x=9^{x+5}
Step-by-step explanation:
3^x=9^{x+5}
x^2-x-6=0
x^4-5x^2+4=0
\sqrt{x-1}-x=-7
\left|3x+1\right|=4
\log _2\left(x+1\right)=\log _3\left(27\right)
3^x=9^{x+5}
If request to solve;
\mathrm{Convert\:}9^{x+5}\mathrm{\:to\:base\:}3
9^{x+5}=\left(3^2\right)^{x+5}
\mathrm{Solve\:}\:x=2\left(x+5\right):\quad x=-10
The two properties are exactly the same when dividing by a positive number. For the division property of equality, dividing by a negative number causes the equal sign to change. Dividing both sides of an inequality by a negative number does not have an effect on the relation symbol.
