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3 years ago

Which of the following occurs when an electron moves from a higher energy shell to a lower energy shell?

1 answer:

7 0

When an electron moves from a higher energy shell to a lower one, energy in the form of light, more specifically a wavelength of a photon is released.

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Plz help! :) :D I will mark you as BRAINLIEST!!!

nadezda [96]

Answer:

Some of the physical and chemical properties of magnesium are:

-The term ‘magnesium’ is derived from the Greek word magnesia, which refers to the name of the place from where it was extracted.

-Magnesium is closely related to manganese and magnetite.

-About 2.1% of the Earth’s crust contains magnesium. This makes magnesium the 6th most found element.

-The biggest deposits of magnesium is found in the seawater. It has been calculated by scientists that a cubic mile of seawater contains about 6 million tons of this element

2nd answer:

Physical Properties of Magnesium: ”I’m a highly stable element, so you can count on me”

Chemical Properties of Magnesium: ”I love to travel but I do corrode aluminum so we won’t be flying off on adventures in airplanes planes anytime soon

Explanation:

Hope this helps you out! UwU

8 0

3 years ago

Determine the volume of a 0.800 M K2Cr2O7 solution required to completely react with 4.24 g of Cu.

Pachacha [2.7K]

<u>Answer:</u> The volume of solution required is 0.0275 L.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of copper = 4.24 g

Molar mass of copper = 63.55 g/mol

Putting values in above equation, we get:

$\text{Moles of copper}=\frac{4.24g}{63.55g/mol}=0.067mol$

The chemical equation for the reaction of potassium dichromate and copper follows:

$K_2Cr_2O_7+3Cu+7H_2SO_4\rightarrow 3CuSO_4+Cr_2(SO_4)_3+K_2SO_4+7H_2O$

By Stoichiometry of the reaction:

3 moles of copper reacts with 1 mole of potassium dichromate.

So, 0.067 moles of copper will react with = $\frac{1}{3}\times 0.067=0.022mol$ of potassium dichromate

To calculate the volume of potassium dichromate, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Moles of potassium dichromate = 0.022 mol

Molarity of solution = 0.800 M

Putting values in above equation, we get:

$0.08mol/L=\frac{0.022mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=0.0275L$

Hence, the volume of solution required is 0.0275 L.

6 0

3 years ago

Help i give more point this time

dmitriy555 [2]

Answer:

It's a type of chemical bond that emerges because of electrostatic force between electrons and positive metal charges.

Explanation:

I don't know if this is what you are looking for but i don't mind if you copy it.

3 0

3 years ago

I NEED HELP ASAP, IM DOING A MASTERY TEST ON PLATO SJJSNSNSJSJSSN PLEASE AND THANK YOU

Hoochie [10]

Condensation is conversion of vapours to liquid

in vapour the molecules of water are far from each other and can move here and there. When a liquid like water condense the molecules come closer to each other.

Thus come closer together and stick to each other.

5 0

3 years ago

Read 2 more answers

If this compounds (N2O) molecular mass is 88g are the empirical and molecular formulas the same as one another or different

Softa [21]

Answer:

Explanation:

Let us examine this problem carefully:

Given compound is N₂O

Molecular mass = 88g

Now,

The empirical formula is the simplest formula of a compound.

The molecular formula is the true formula of the compound that shows that actual ratios of the atoms in a compound.

To find if they both have the same molecular and empirical formula, they must have the same molecular mass.

For N₂O;

Molecular mass = 2(14) + 16 = 44g/mole

But the true and given molecular formula of the compound is 88g/mole

This shows that the compound given is the empirical formula of the compound.

Molecular formula:

molecular mass of empirical formula x n = molecular mass of molecular formula

n = $\frac{88}{44}$ = 2

Molecular formula of compound = 2(N₂O) = N₄O₂

Therefore the empirical and molecular formulas are not the same

8 0

3 years ago