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Reptile [31]
3 years ago
14

Which of the following occurs when an electron moves from a higher energy shell to a lower energy shell?

Chemistry
1 answer:
AlexFokin [52]3 years ago
7 0
When an electron moves from a higher energy shell to a lower one, energy in the form of light, more specifically a wavelength of a photon is released.
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tres pensamientos negativos sobre el C0Vid-19 que se vive en la actualidad y luego transformemos a pensamientos positivos.
katrin2010 [14]

Answer:

Bueno,

Explanation:

Tres pesnamientos negativos sobre el C0Vid-19 son,

- Encerrados en la casa

- Tener que ponerse mascara

- Todos los lugares divertidos cerrados

Convertidos en positivos:

- Pasamos mas tiempo de calidad en familia.

- Nos protejemos unos a otros.

- Descansan un poco todas las personas que se han pasado toda la vida trabajando.

7 0
3 years ago
Read 2 more answers
What is the decay mode of radium-226?
inn [45]

Answer:

Radium-226 is a radioactive decay product in the uranium-238 decay series and is the precursor of radon-222. Radium-228 is a radioactive decay product in the thorium-232 decay series. Both isotopes give rise to many additional short-lived radionuclides, resulting in a wide spectrum of alpha, beta and gamma radiations.

6 0
3 years ago
Convert 1176 mmHg to kPa
OLEGan [10]

Answer:

 156.8kPa

Explanation:

The problem here is to convert mmHg to kPa;

We have been given:

            1176mmHg and the problem is to convert to kPa;

  1000Pa = 1kPa

               1 mmHg  =  133.322Pa

               1176mmHg will give  1176 x 133.322  = 156787.1Pa

To kPa;

             156.8kPa

8 0
2 years ago
Metallic copper is formed when aluminum reacts with copper(ii) sulfate. how many grams of metallic copper can be obtained when 5
exis [7]
Answer is: 127 grams <span>rams of metallic copper can be obtained.
</span>Balanced chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54.0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 54 g ÷ 27 g/mol.
n(Al) = 2 mol.
m(CuSO₄) = 319 g.
n(CuSO₄) = 319 g ÷ 159.6 g/mol.
n(CuSO₄) = 2 mol; limiting reactant.
From chemical reaction: n(CuSO₄) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
n(Cu) = 2 mol · 63.55 g/mol.
n(Cu) = 127.1 g.
8 0
3 years ago
A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula
ki77a [65]
The standard atomic weight of a C is 12, and the standard atomic weight of a H is 1.  So to find molar ratio of C and H in the compound: 60.0/12=5, 5.05/1=5. This means the molar ratio of C and H is 5:5, thus 1:1.  Assuming the molecular formula is CnHn, to find molar mass: 12n + 1n = 78.12.  n=78.12/(12+1) = 6.  So the compound's molecular formula is C6H6, benzene.
4 0
3 years ago
Read 2 more answers
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