Answer:
-0.64525g
Explanation:
t = Time taken for the car to stop
u = Initial velocity = 95 km/h
v = Final velocity = 0 km/h
s = Displacement
a = Acceleration
Equation of motion
Converting to m/s²
g = Acceleration due to gravity = 9.81 m/s²
Dividing both the accelerations, we get
Hence, acceleration of the car is -0.64525g
Answer:
4500.5 nutritional calories per gram
Explanation:
Heat lost by the new candy = heat gained by the bomb calorimeter.
Heat gained by the bomb calorimeter = c×ΔT
where c = heat capacity of the calorimeter = 32.20 KJ/K = 32200 J/K
ΔT = change in temperature = 2.69°C = 2.69 K.
Heat gained by the bomb calorimeter = 32200 × 2.69 = 86618 J
Heat lost by the new candy = heat gained by the bomb calorimeter = 86618 J = 20702.2 calories
4.60 g of the new candy lost this amount of calories by undergoing combustion,
The amount of calories per g = 20702.2 calories/4.6 g = 4500.5 calories per gram
Answer:
A thin, taut string tied at both ends and oscillating in its third harmonic has its shape described by the equation y(x,t)=(5.60cm)sin[(0.0340rad/cm)x]sin[(50.0rad/s)t]y(x,t)=(5.60cm)sin[(0.0340rad/cm)x]sin[(50.0rad/s)t], where the origin is at the left end of the string, the x-axis is along the string, and the y-axis is perpendicular to the string. (a) Draw a sketch that shows the standing-wave pattern. (b) Find the amplitude of the two traveling waves that make up this standing wave. (c) What is the length of the string? (d) Find the wavelength, frequency, period, and speed of the traveling waves. (e) Find the maximum transverse speed of a point on the string. (f) What would be the equation y(x, t) for this string if it were vibrating in its eighth harmonic?
