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alisha [4.7K]
4 years ago
6

A bee travels 7.6 m in 38 seconds. what is it’s velocity?

Physics
1 answer:
ahrayia [7]4 years ago
6 0

Answer:

Velocity=0.2m/s

Explanation:

Velocity=displacement / time

Velocity=7.6m/38s

Velocity=0.2m/s

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HELP PLZ ASAP!!!!!
zubka84 [21]

Answer:

C. Oxygen combines with carbon dioxide

Explanation:

B i o l o g y

Also, oxygen is a reactant and carbon dioxide is a product of cellular respiration that does not combine during this process

Hope it helps

5 0
3 years ago
A bicycle has a momentum of 25.00 kg·m/s and a velocity of 2.5 m/s. What is the bicycle’smass?
tigry1 [53]

Answer:

10 kg

Explanation:

p=ma

25=2.5m

m=25/2.5

m=10 kg

mark as brainliest plzzzzz

6 0
3 years ago
A particle whose speed is 50 m/sec moves along the line from A(2,1) to B (9,25)
WINSTONCH [101]

First, calculate for the distance between the given points A and B by using the equation,

<span>                                                D = sqrt ((x2 – x1)2 + (y2 – y1)2)</span>

 

Substitute the known values:

<span>                                                D = sqrt((9 – 2)2 + (25 – 1)2)</span>

<span>                                                D = 25 m</span>

 

I assume the unknown here is the time it would require for the particle to move from point A to B. This can be answered by dividing the calculated distance by the speed given above.

<span>                                                t = (25 m)/ (50 m/s) = 0.5 s</span>

 

<span>Thus, it will take 0.5s for the particle to complete the route. </span>

3 0
3 years ago
You short-circuit a 18 volt battery by connecting a short wire from one end of the battery to the other end. if the current in t
mina [271]
The relationship between the voltage and the current in the circuit is:
\Delta V = RI
where \Delta V is the voltage difference, R the resistance of the circuit (and therefore, the resistance of the battery) and I the current flowing in the circuit. By using I=19 A and \Delta V = 18 V, we can find the internal resistance of the battery:
R= \frac{\Delta V}{I}= \frac{18 V}{19 A}=0.95 \Omega
3 0
3 years ago
A copper wire 12 cm long and a mass of 16 g is in a magnetic field of 1.2 T oriented perpendicular to the wire. What current wou
Ugo [173]

Answer:

Current, I = 1.08 A

Explanation:

Given that,

Length of the copper wire, l = 12 cm = 0.12 m

Mass of the wire, m = 16 g = 0.016 kg

Magnetic field, B = 1.2 T

The magnetic field is oriented perpendicular to the wire. We need to find the current in the wire.

Magnetic force, F = BIL

Force of gravity, F' = mg

F' = F

BIL=mg

I=\dfrac{mg}{BL}

I=\dfrac{0.016\times 9.8}{1.2\times 0.12}

I = 1.08 A

So, the current through the wire is 1.08 A. Hence, this is the required solution.

8 0
4 years ago
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