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3 years ago

8

HELP PLZ ASAP!!!!!

1 answer:

zubka84 [21]3 years ago

5 0

Answer:

C. Oxygen combines with carbon dioxide

Explanation:

B i o l o g y

Also, oxygen is a reactant and carbon dioxide is a product of cellular respiration that does not combine during this process

Hope it helps

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A neutron star is moving in outer space at 4,000 km/hr. What happened to the star that set it in motion on it's current course?

astra-53 [7]

Answer:

d

a balanced force acted on it and propelled it to 4,000 km/hr

Explanation:

For the neutrons star which is moving in outer space at 4,000 km/hr, it could only be possible as a result of the balanced force which had already acted on it. <em>This is based on newton's law of motion which states that 'To every action, there is equal and opposite reaction'. </em>

4 0

3 years ago

A penny is dropped from the Statue of Liberty

Brrunno [24]

Answer:

a) The velocity is 2.94m/s

b) 0.441

Explanation:

a) Assume gravity is 9.8m/s^2

Use the equation below to solve for the velocity at 0.30 seconds

$vf=vi+at$ ,

vf =unknown velocity vi= initial velocity vi=0m/s a= 9.8m/s^2 t=0.30seconds

Step 1: Substitute the variables with the knowns

$vf=0m/s+(9.8m/s^2)*0.30seconds$

Step 2: Solve

$vf=2.94m/s$

b)

Use the equation below to solve for the displacement at 0.30 seconds

$x=vit+\frac{1}{2} at^{2}$

Step 1: Substitute the same variables with the knowns

$x=\frac{1}{2}*(9.8m/s^2)*(0.30seconds)^{2}$

Note that vi*t=0 as vi=0m/s

Step 2: Solve

x=0.441m

5 0

3 years ago

Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of

Pachacha [2.7K]

Answer:

<em>The frequency changes by a factor of 0.27.</em>

<em></em>

Explanation:

The frequency of an object with mass m attached to a spring is given as

$f$ = $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

where $f$ is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

$f_{n}$ = $\frac{1}{2\pi } \sqrt{\frac{k}{14m} }$

simplifying, we have

$f_{n}$ = $\frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }$

$f_{n}$ = $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$

if we divide this final frequency by the original frequency, we'll have

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ ÷ $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ x $2\pi \sqrt{\frac{m}{k} }$

==> 1/3.742 = <em>0.27</em>

7 0

3 years ago

A ship sails west for 100km and then south for 100km. What is the displacement?

ale4655 [162]

$\sf \vec{w}=100$

$\sf \vec{s}=100$

For displacement apply Pythagorean theorem

$\\ \rm\hookrightarrow 100^2+100^2$

$\\ \rm\hookrightarrow 10000+10000$

$\\ \rm\hookrightarrow 20000$

4 0

2 years ago

A motorcycle is moving at a speed of 21 m/s. The driver applies the brakes, giving hum an acceleration of -2.4 m/s^2. After 2 se

WARRIOR [948]

<h3><u>Answer;</u></h3>

B. 16.2 m/s

<h3><u>Explanation</u>;</h3>

Using the equation;

v = u + at; where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken;

u = 21 m/s, a= -2.4 m/s^2 and t = 2 seconds

Therefore;

v = 21 + ((-2.4) × 2)

= 21 - 4.8

<u> = 16.2 m/s</u>

6 0

3 years ago