1st week: 2b + 3
2nd week: 2(2b + 3) = 4b + 6
3rd week: 2(4b + 6) = 8b + 12
If 8b + 12 is $477, $477 - 12 must be 8b. $477 - 12 = $465 / 8 = $58.125 / .13
2b + 3 = 2 x 58.13 + 3 = $116.26 + 3 =
$119.26 is your answer
Answer:
- a) P(x) = 32000*1.04^x
- b) $37435
- c) During year 7
Step-by-step explanation:
<u>Given</u>
- Initial pay = $32000
- Increase rate = 4%
a. <u>Formula</u>
b. Year 5 is after 4 years, so we are looking for the value of P(4)
- P(4) = $32000*1.04^4 = $37435
c. <u>P(x) = 40000, x = ?</u>
- 40000 = 32000*1.04^x
- 1.04^x = 40000/32000
- 1.04^x = 1.25
- log 1.04^x = log 1.25
- x = log 1.25 / log 1.04
- x = 5.69, this is 6 years after
The required number of the years is 6 + 1 = 7
It's probably A (I can't tell you for certain, because I can't see the image, but the other options seem illogical).
Answer:
Step-by-step explanation:
Answer:
-543
Step-by-step explanation:
For every value of k, you substitute 9 and for every value of c, you substitute 2
-6((8x(9)+ 9(2)) - 3
so order of operations says you should do what's in the parentheses first.
8 x 9= 72 and 9 x 2 = 18
so now you have -6 ( 72 + 18) -3
Finish the calculating inside the parentheses: -6 (90) -3
and now multiply -6 and 90 before you subtract 3
-6 x 90 = -540
-540 - 3 = -543