The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
brainly.com/question/14290572
#SPJ2
Answer:
Step-by-step explanation:
all we have to do is plug in 2 for x into the equation:
-8(2) + 5 -2(2) -4 + 5(2)
-16 + 5 -4 -4 + 10
-11 -8 + 10
-19 + 10
the answer is
-9
to simplify the equation we’ll combine like terms
-8x + 5 -2x -4 + 5x
-10x + 1 + 5x
-5x + 1
now we’ll plug in 2 for x
-5(2) + 1
-10 + 1
the answer is still
-9
Answer:4.3
You round to the tenths place
Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:
The magnitude of vecor v is given to be 10. So we can write:
Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.
The point in option d, satisfies the equation.
Thus, the answer to this question is option D
Answer:
D.
Step-by-step explanation:
-2*-3=6 -2*5=-10. -2*1=-2
-2*8=-16. -2*-2=4. -2*3=-6
-2*2=-4. -2*1=-2. -2*-4=8
