Answer:
The answer to your question is: V1 = 27.8 ml of HCl 18 M
Explanation:
Data
HCl = [18M]
HCl Vol = ?
HCl = [ 2M]
HCl vol = 250 ml
Formula
V₁ C₁ = V₂ C₂
V₁ = V₂ C₂ / C₁
Process (substitution)
V₁ = (250)(2) / 18
V₁ = 500 / 18
V1 = 27.8 ml
HCl ----------> H(+) + Cl(-)
0,0045-x.........x...........x
0..................0,0045...0,0045
pH = -log[H+]
pH = -log[0,0045]
pH = 2,347
pOH = 14-pH
pOH = 14-2,347
pOH = 11,653
pOH = -log[OH-]
[OH-] = 10^-pOH
[OH-] = 10^-11,653
[OH-] = 2,2233·10^-12 mol/dm³
Volume is the amount of space an object takes up
Let us see the structure of ascorbic acid
As shown there is no COOH group however the OH group can lose a proton and forms conjugate base
The conjugate base formed is stabilized due to resonance
More the stability of conjugate base more the strength of acid
Hence ascorbic acid behaves as an acid
A solution <span>has a uniform composition and is only able to be separated by chemical means.</span>
