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lidiya [134]
3 years ago
6

Why does the state of matter change for the alliance family?

Chemistry
2 answers:
Andru [333]3 years ago
5 0

Answer:

i

Explanation:

in organic chemistry an alkane also known as paraffin the standard entalphy changes of combustion change in cH for alkane increase by about 650 kJ/mol both of these process raise the octane number of the substance

gtnhenbr [62]3 years ago
3 0
U done got the answer
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Can you Find the quotient of 1/4 of 3
Romashka [77]

Answer: 1/12

1/4 divided by 3/1

KCF:Keep the first fraction, Change the sign to muplication, Flip the second fraction.

1/4* 31

1*1=1

4*3=12

1/12

7 0
4 years ago
2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
azamat

Answer:

K=1.12x10^9

Explanation:

Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

K=\frac{(0.95)^2}{(0.0024)^2(0.00014)}\\\\K=1.12x10^9

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.

Best regards!

4 0
3 years ago
The gas in a cylinder has a volume of 8 liters at a pressure of 101 kPa. The pressure of the gas is increased to 206 kPa. Assumi
Arlecino [84]
The pressure of the gas is increased<span> to 224 </span><span>kPa</span>
3 0
3 years ago
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
Which microscope came out first
victus00 [196]

Answer:

compound microscope

Explanation:

6 0
3 years ago
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