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Triss [41]
3 years ago
13

Ted's company has received an order to print 106 pages. Ted's company has 100 machines, each of which can print 104 pages a day.

Mathematics
2 answers:
DENIUS [597]3 years ago
7 0
Number machines=100=10² machines.
number pages/1 machine=10⁴ pages/ machine.

number pages that can print 100 machines in a day=
=10² machines * 10⁴ pages/ machines=10²⁺⁴ pages=10⁶ pages/day.

necessary days to print 10⁶ pages=number pages/ number pages that can print 100 machines in a day.

necessarry days to print 10⁶ pages=10⁶ pages / 10 ⁶ pages/day=10⁶⁻⁶ days=
=10⁰ days=1 day.

1 day for print 10⁶ pages, whith 100 machines. 
AysviL [449]3 years ago
3 0
Number machines=100=10² machines.
number pages/1 machine=10⁴ pages/ machine.

number pages that can print 100 machines in a day=
=10² machines * 10⁴ pages/ machines=10²⁺⁴ pages=10⁶ pages/day.

necessary days to print 10⁶ pages=number pages/ number pages that can print 100 machines in a day.

necessarry days to print 10⁶ pages=10⁶ pages / 10 ⁶ pages/day=10⁶⁻⁶ days=
=10⁰ days=1 day.

1 day for print 10⁶ pages, whith 100 machines. 
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Determine if the side lengths could form a triangle. Use an inequality to prove your answer.
podryga [215]

9514 1404 393

Answer:

  a) no

  b) yes

  c) maybe (no)

Step-by-step explanation:

There are two versions of the triangle inequality. One requires ...

  a + b > c

for any triple of side measures a, b, c.

The other allows ...

  a + b ≥ c

which admits "triangles" that have zero height and look like line segments.

Most questions asking "do these lengths form a triangle" are concerned with the "greater than" case, and disallow the "or equal to" case.

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a)

  16+21=37\ngtr39\qquad\text{not a triangle}

b)

  27+34=61>58\qquad\text{could be a triangle}

c)

  9+29=38\ge38\qquad\text{could be a triangle if "equal to" is allowed}

7 0
3 years ago
Use the equation p = 831 where p = pressure and
Hoochie [10]
Cccvvcv 1000+10000 equal to 1000
6 0
3 years ago
◕ A dealer sold a photocopy machine at Rs 4200 with 13% VAT to a retailer. The retailer added transportation cost of Rs 250 , pr
satela [25.4K]

<u>Given </u><u>:</u><u>-</u>

  • A dealer sold a photocopy machine at Rs 4200 with 13% VAT to a retailer.
  • The retailer added transportation cost of Rs 250 , profit Rs 300 and local tax Rs 150 and sold to consumer .
  • Customer has to pay 13% VAT .

<u>To </u><u>Find </u><u>:</u><u>-</u>

  • Amount to be paid by the customer .

<u>Sol</u><u>u</u><u>tion </u><u>:</u><u>-</u>

Here , according to the question ,

\sf\dashrightarrow Cost\ of \ machine \ = \ Rs 4200

\sf\dashrightarrow VAT = 13\%

Therefore cost after adding VAT ,

\sf\dashrightarrow Cost = Cost_{initial}+13\% of Cost_{initial}\\

\sf\dashrightarrow Cost = Rs4200 + Rs 4200 \times \dfrac{13}{100}\\

\sf\dashrightarrow Cost = Rs4200 + Rs546\\

\sf\dashrightarrow \bf{ Cost = Rs 4746}

Again the values added by the retailer before selling to customer ,

  • Transport = Rs 250
  • Profit = Rs 300
  • Tax = Rs 150

Therefore total cost after adding these ,

\sf\dashrightarrow Cost = Rs( 4746+ 250+ 300 + 150 )\\

\sf\dashrightarrow\bf { Cost = Rs 5446}

Again Selling price after addition of 13% VAT ,

\sf\dashrightarrow SP = Rs 5446 + 13\% \ of \ Rs 5446\\

\sf\dashrightarrow SP = Rs 5446 + \dfrac{13}{100}\times 5446 \\

\sf\dashrightarrow SP = Rs (5446 + 707.98) =  Rs ( 5446 + 708)\\

\sf\dashrightarrow \underline{\underline{\bf SP_{to\ the \ customer} = Rs 6154}}

<u>Hence </u><u>the </u><u>amount </u><u>to </u><u>be </u><u>paid </u><u>by </u><u>the </u><u>customer </u><u>is </u><u>Rs </u><u>6</u><u>1</u><u>5</u><u>4</u><u> </u><u>.</u>

3 0
2 years ago
Read 2 more answers
What is the value of x to the nearest tenth?
uranmaximum [27]

Check the picture below.

3 0
3 years ago
Solve for x.<br><br> 2/3(x−7)=−2
zaharov [31]
2/3x - 14/3 = -2
3(2/3x - 14/3) = -2(3)
           2x - 14 = -6
                   2x = -6 + 14
                   2x = 8
                     x = 8/2
                     x= 4

hope this helps :)



5 0
3 years ago
Read 2 more answers
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