Answer:
Express these numbers in atomic mass units ("u"). Note the amounts of atoms of all the component in HNO3, which are 1 atom of Hydrogen, 1 atom of Nitrogen and 3 atoms of Oxygen. ( I asked my teacher about this too)
Explanation:
Answer:
10.4664 grams of CO
Explanation:
Remark
There's a couple of things you must look out for in this question.
1. The use of the term atoms. There are 2 atoms in each mol of CO
2. You need to divide by 2 to find the number of molecules which will lead to moles.
<u>Step one</u>
Divide the number of atoms by 2
4.50 e^23 / 2 atoms = 2.25 * 10^23 molecules.
<u>Step Two</u>
Find the number of moles of CO
1 mol of anything is 6.02 * 10^23 molecules in this case
x = 2.25 * 10^23 molecules
1/x = 6.02 * 10^23/2.25 * 10 ^23 Cross multiply
1 * 2.25 * 10^23 = 6.02*10^23 * x Divide by 6.02 * 10^23
2.25 * 10 ^ 23 / 6.02 * 10^23 = x
x = .3738 moles of CO
<u>Step Three</u>
Find the gram molecular mass of CO
C = 12
O = 16
1 mole = 12 + 16 = 28 grams.
<u>Step Four</u>
Find the number of gram in 0.3738 mols
1 mol = 28 grams
0.3738 mol = x Cross multiply
x = 28 * 0.3738
x = 10.4664 grams
I think that it is D because the higher the molecular mass, the higher it's boiling point. I hope that helped:) Bye!
1 mole of Ethanol molecule contains an Avogadro Number of molecules
1 mole of Ethanol molecule contains 6.02 * 10²³ molecules
3.5 moles of Ethanol will then contain: 3.5 * 6.02 * 10²³
= 2.107 * 10²⁴ molecules.
<span>Given:
acid-dissociation constants of sulfurous acid</span>:
Ka1 = 1.7 * 10^(-2)
Ka2 = 6.4 * 10^(-8) at
25.0 °C.
aqueous solution of
sulfurous acid = 0.163 M
x² / (0.163 - x) = 1.7 * 10^(-2)
You simplify it to:
<span>x² / (0.163) = 1.7 *10^(-2) </span>
x = 0.052640 M
pH = 1.28
<span>
So, the pH of a 0.163 M aqueous solution of sulfurous acid is 1.28.</span>
To add, aqueous solutions of sulfur dioxide purpose
are as disinfectants and reductant, as are solutions of sulfite<span> salts
and </span>bisulfite. By accepting another oxygen<span> atom, they
are </span>oxidised to sulfuric
acid or sulfate.
