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Advocard [28]
3 years ago
11

Need Some Quick Help, Please :)

Chemistry
1 answer:
Ray Of Light [21]3 years ago
6 0
I think that it is D because the higher the molecular mass, the higher it's boiling point. I hope that helped:) Bye!
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In the compound H2O, the electrons in the bonds are unequally shared between oxygen and hydrogen, forming ____. (1 point)
Aloiza [94]
<span>polar bonds due to high difference . In electronegativity of oxygen and hydrogen.</span>
5 0
3 years ago
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Uranium (VIII) Sulfide formula
tresset_1 [31]

Answer:

US₂

Explanation:

Uranium sulfide (US₂)

Uranium atomic symbol = U

Sulfur atomic symbol = S

Uranium valency = +4

Sulfur valency = -2

So;

Uranium sulfide (US₂)

8 0
3 years ago
Which measure of a gas does the expression
Usimov [2.4K]

Answer:

A. volume

Explanation:

Generally the equation for the  ideal gas  is mathematically given as  

PV=nRT

Where  

P=pressure  

V=volume  

R=gas constant  

n=Number of Moles  

T=Temperature

 

Therefore  

V=nRT/P  

Option A

For more information on this visit

brainly.com/question/17756498

7 0
3 years ago
The town of Natrium, West Virginia, derives its name from the sodium produced in the electrolysis of molten sodium chloride (NaC
Alona [7]

Explanation:

The reaction equation will be as follows.

           Na^{+} + e^{-} \rightarrow Na(s)

Hence, moles of Na = moles of electron used

Therefore, calculate the number of moles of sodium as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{4500 g}{23 g/mol}    (as 1 kg = 1000 g)

                             = 195.65 mol

As,     Q = n \times F       where F = Faraday's constant

              = 195.65 mol \times 96500 C

              = 1.88 \times 10^{7} mol C

Relation between electrical energy and Q is as follows.

               E = Q \times V

Hence, putting the given values into the above formula and then calculate the value of electricity as follows.

              E = Q \times V

                 = 1.88 \times 10^{7} \times 5

                 = 9.4 \times 10^{7} J

As 1 J = 2.77 \times 10^{-7} kWh

Hence,      \frac{9.4 \times 10^{7}}{2.77 \times 10^{-7}} kWh

                = 3.39 kWh

Thus, we can conclude that 3.39 kilowatt-hours of electricity is required in the given situation.

7 0
4 years ago
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Which of the following elements is a metalloid?
Deffense [45]
The answer to your question would be silicon. I hope this helped!!!
4 0
3 years ago
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