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3 years ago

This is a diagram of the ear.

Physics

1 answer:

____ [38]3 years ago

6 0

Answer:

Hello, Your answer should be is Auditory Nerve

Explanation:

Because the "Auditory Nerve" bundle of nerves that carries hearing information, The cochlear nerve, also known as the acoustic nerve, is the sensory nerve that transfers auditory information from the cochlea (auditory area of the inner ear). Its not A, because the "Optic nerve" second pairs of cranial transmitting impulses to the brain. Its not really C, Because the "Cochlea" is a spiral cavity that is inside of the inner ear. And its not D, because the "Stirrup" is the stapes or stirrup is on the bone, by the middle ear of humans and mammels too. So your best answer will be Auditory Nerve.

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Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli

Thepotemich [5.8K]

Answer:

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

Explanation:

Given:

Mass of Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = $v_{f}=?$

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

$m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}$

Substituting the values we get

$2\times 14 + 5\times 0 =(2+5)\times v_{f}$

$v_{f}=\dfrac{28}{7}=4\ m/s$

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

8 0

3 years ago

The frequency of the George Washington Bridge is 2.05 Hz. What is its period?

Zina [86]

Answer: 0.5 seconds

Explanation:

Given that:

Frequency of the George Washington Bridge F = 2.05 Hz

Period T = ?

Recall that frequency is the number of cycles a wave can complete in one second. Hence, frequency is the inverse of period.

i.e F = 1/T

2.05Hz = 1/T

T = 1/2.05Hz

T = 0.488 seconds (Rounded to the nearest tenth as 0.5seconds)

Thus, the period of the George Washington Bridge is 0.5 seconds

6 0

3 years ago

What is the pressure transmitted in the liquid on a hydraulic pump where an elephant with a weight of 40 000 N is placed on top

Elodia [21]

Answer:

What is the pressure transmitted in the liquid on a hydraulic pump where an elephant with a weight of 40 000 N is placed on top of the large piston with an area of 40 m2. The small piston area is 4 m2.

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3 years ago

Two pulses are moving along a string one pulse is moving to the right and the second is moving to the left. Both pulses reach po

MatroZZZ [7]

Answer:

Constructive interference

Explanation:

- This is an example of a standing wave produced when two ends of a string are oscillated in the same plane. The displacement of of point on two ends oscillates vertically.

- We are given that two pulses move along the string each coming towards each other and meet at a common point ( P ).

- Each pulse have their own magnitude or displacement in the vertical plane. If the pulses are to meet at a common point at the same instant, then they interfere with each other constructively.

- Where constructive interference of two pulses is the addition of magnitudes of induvidual pulses and form a single puls of the constructed magnitude.

magnitude ( New pulse ) = magnitude (Pulse 1) + magnitude (Pulse 2)

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3 years ago

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Tuberculosis. Reason: I just took the test and got it right

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3 years ago