Answer:
1) Conduction
2)Covection
3)Radiation
4)Convection (Land breeze one of the application of convection of heat)
5) Convection
6)Radiation
7) Radiation
8)Conduction
9) Conduction
10) Radiation
Hope it helps
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Answer:
Check the explanation
Explanation:
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
The image is virtual
The image is upright
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
Kindly check the diagram in the attached image below.
Answer:
7.5 m
Explanation:
= initial speed of the ball = 8 m/s
= angle of launch = 40° deg
Consider the motion along the vertical direction :
= initial velocity along vertical direction =
= 8 Sin40 = 5.14 m/s
= acceleration along vertical direction = - 9.8 m/s²
= time of travel
= vertical displacement = - 1 m
Using the kinematics equation


= 1.22 sec
Consider the motion along the horizontal direction :
= initial velocity along horizontal direction =
= 8 Cos40 = 6.13 m/s
= acceleration along vertical direction = 0 m/s²
= time of travel = 1.22 sec
= horizontal displacement = ?
Using the kinematics equation


= 7.5 m