Answer:
1.
2.
Explanation:
Hello,
1) In this case, the reaction is:
Thus, since 1.595 kg of calcium carbonate, whose molar mass is 100 g/mol, is decomposed, the following moles of carbon dioxide are produced:
Then, by using the ideal gas equation we can compute the volume of carbon dioxide:
2) In this case, the reaction is:
Thus, lead (II) chloride is the precipitate. In such a way, we first identify the limiting reactant by firstly computing the moles of potassium chloride and lead (II) nitrate with the volumes and the molarities:
Next, we compute the moles of potassium chloride consumed by 0.567 moles of lead (II) nitrate by using their 2:1 molar ratio:
Therefore, as just 0.371 moles of potassium chloride are available we say it is the limiting reactant, for that reason, the grams of lead (II) chloride, whose molar mass is 278.1 g/mol, precipitate finally result:
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