Soution A has a higher osmolarity than solution B and is hyperosmotic.
Solution be is hyposmotic. Neither are isosmotic.
Answer:
0.87 pg
Explanation:
<em>GenAlex Medical, a leading manufacturer of medical laboratory equipment, is designing a new automated system that can detect normal levels of dissolved triiodothyronine (230. to 660 pg/dL), using a blood sample that is as small as 380 μL. Calculate the minimum mass in picograms of triiodothyronine that the new system must be able to detect. Be sure your answer has the correct number of significant digits.</em>
Step 1: Convert 380 μL to deciliters
We will use the following conversion factors.
380 μL × 1 L/10⁶ μL × 10 dL/1 L = 3.8 × 10⁻³ L
Step 2: Calculate the minimum mass of triiodothyronine that can be found in a 3.8 × 10⁻³ L blood sample
Since we are looking for the minimum mass, we will use the lower limit of the concentration interval (230. pg/dL).
3.8 × 10⁻³ L × 230. pg/dL = 0.87 pg
Answer:
2H₂O₂ → 2H₂O + O₂
Explanation:
H₂O₂ → H₂O + O₂
The above equation can be balance as illustrated below:
H₂O₂ → H₂O + O₂
There are 2 atoms of O on the left side and a total of 3 atoms on the right side. It can be balance by putting 2 in front of H₂O₂ and 2 in front of H₂O as shown below:
2H₂O₂ → 2H₂O + O₂
Now, the equation is balanced.
**** check ****
Element >>> Left Side >>> Right Side
H >>>>>>>>> 4 >>>>>>>>> 4
O >>>>>>>>> 4 >>>>>>>>> 4
S₂O₈²⁻
(aq) + 2I⁻
(aq) → I₂(aq) + 2SO₄
²⁻(aq)
2S₂O₃²⁻
(aq) + I₂(aq) → S₄O₆²⁻
(aq) + 2I⁻
(aq)
<u>Explanation:</u>
S₂O₈²⁻
(aq) + 2I⁻
(aq) → I₂(aq) + 2SO₄
²⁻(aq)
To measure the rate of this reaction we must measure the rate of concentration change of one of the reactants or products. To do this, we will include (to the reacting S₂O₈
²⁻ and I⁻
i) a small amount of sodium thiosulfate, Na₂S₂O₃,
ii) some starch indicator.
The added Na₂S₂O₃ does not interfere with the rate of above reaction, but it does consume the I₂ as soon as it is formed.
2S₂O₃²⁻
(aq) + I₂(aq) → S₄O₆²⁻
(aq) + 2I⁻
(aq)
This reaction is much faster than the previous, so the conversion of I2 back to I⁻ is essentially instantaneous.
![rate = \frac{dI2}{dt} = \frac{1/2 [S2O3^2^-]}{t}](https://tex.z-dn.net/?f=rate%20%3D%20%5Cfrac%7BdI2%7D%7Bdt%7D%20%3D%20%5Cfrac%7B1%2F2%20%5BS2O3%5E2%5E-%5D%7D%7Bt%7D)
It would be Rubidium chloride.
