Answer:
0.9%
Explanation:
At the instance where you add RBCs to a solution of 0.9% NaCl, they will maintain their shape as well as their size, this is simply to indicate an equilibrium. That entails that the solution is isotonic to the RBCs. This must mean that the concentration of solutes on each side must be equal otherwise osmotic pressure would force water either in or out of the membrane. Therefore, one can also safely assume that RBC's also have a solute concentration of 0.9%.
So you would do 12.99 / 4 which = about 3.25 per liter of gas
Answer:
The answer to your question is 308.1 kPa
Explanation:
Data
Volume 1 = V1 = 4.75 l
Pressure 1 = P1 = 120 kPa
Volume 2 = V2 = 1.85 l
Pressure 2 = ?
Process
To solve this problem use Boyle's law.
P1V1 = P2V2
- Solve for P2
P2 = P1V1 / V2
- Substitution
P2 = (120 x 4.75) / 1.85
-Simplification
P2 = 570 / 1.85
-Result
P2 = 308.1 kPa
