Answer: 2CO2, 8CO2
Explanation:
During glycolysis one molecule of glucose is oxidized to two molecules of pyruvic acid (3 carbon molecule). Pyruvic acid is converted to acetyl CoA(2 carbon molecule) by the pyruvate dehydrogenase complex.
For each acetic acid that enters the citric acid cycle 2 molecules of CO2 is given off.
For one glucose molecule produces 2 acetyl CoA
2 acetyl groups + 6 NAD+ + 2 FAD + 2 ADP + 2 Pi yields 4 CO2 + 6 NADH + 6 H+ + 2 FADH2 + 2 ATP.
Hence 4 molecules of acetic acid is completely oxidized to 8 molecules of CO2.
Using the ideal gas law, the number of moles SO2 is equal to PV/RT, or pressure times volume divided by the gas constant and temperature. This is 14.5*1.1/((2.5+279.15)*.082), or 0.66 moles. Since one mole CaSO3 is consumed for every mole SO2 generated, 0.66 moles of CaSO3 are consumed. CaSO3 has a molar mass of 40+32+16*3=120 grams, so .66 moles of CaSO3 is equal to 80 grams, our final answer.
The true is that both substances will have 2 * 6.02* 10^23 = 12.04 * 10^23 particles (may be molucules or atoms(.
Also, the two moles of each substance will have different masses, because you have to multiply the number of moles of each substance by the respective molar mass (or atomic mass).
the answer is in the picture, btw the molar mass for the first one is wrong, it should be 77.98, and the final product is 2.32
Answer:
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