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Art [367]
4 years ago
15

Which lab equipment tool would you use to measure exactly 4 ml of water​

Chemistry
1 answer:
11Alexandr11 [23.1K]4 years ago
4 0
You would use a Graduated Cylinder
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The temperature of a substance is a measure of its particles in
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Brownian(Chaotic) motion
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4 years ago
A force is applied to an object on a frictionless surface. it produces an acceleration of 3m/s2.
Anit [1.1K]
Answer:

no

explanation:

why
4 0
3 years ago
To a 25.00 mL volumetric flask, a lab technician adds a 0.250 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
Basile [38]

Answer: The number of moles of the weak acid in the solution is 0.00396

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      

a) {\text{Moles of}KOH=0.0846M\times 0.04683L=0.00396mol

The balanced chemical reaction is:

HA+KOH\rightarrow KA+H_2O  

1 mole of base uses = 1 mole of HA  

0.00396  moles of base use = \frac{1}{1}\times 0.00396=0.00396 moles of HA  

Thus the number of moles of the weak acid in the solution is 0.00396

6 0
3 years ago
What would the formula be for this model above?
Daniel [21]

Answer:

CH4

Explanation:

A= CH4

8 0
3 years ago
Two gas-containers, A and B, are connected with a valve. The first container, A, has a volume of 135 mL, and the second containe
stiv31 [10]

Answer:

85.5 mmHg is the pressure of the gas sample when the valve is opened.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in container A = 165 mmHg

P_2 = final pressure of gas = ?

V_1 = initial volume of gas in container A= 135 mL

V_2 = final volume of gas = 135 mL + 117 mL = 252 mL

T_1 = initial temperature of gas in container A = 22.5^oC=273+22.5=295.5 K

T_2 = final temperature of gas = 12.7^oC=273+12.7=285.7K

Now put all the given values in the above equation, we get:

P_2=\frac{P_1V_1\times T_2}{T_1\times V_2}

=\frac{165 mmHg\times 135 mL\times 285.7 K}{295.5 K\times 252 mL}

P_2=85.5 mmHg

85.5 mmHg is the pressure of the gas sample when the valve is opened.

8 0
4 years ago
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