Solve for a.
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We are given zeros of the polynomial : 7, -11, and 2 + 8i.
Note: The radical zero always comes with the pair of plus and minus sign.
Therefore, another zero would be 2-8i.
Now, in order to find the polynomial with the zeros 7, -11, 2 + 8i and 2-8i, we need to find the factors of the polynomial.
The factors of the polynomial would be (x-7)(x+11)(x-2-8i)(x-2+8i).
Let us multiply those factors to get the standard form of the polynomial.
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