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torisob [31]
3 years ago
7

Which answer, to the correct number of significant figures, is closest to the true value of the expression: (9.1 x 104 )(1.1 x 1

0-5 )(log 10-13)(1000)g
Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer : The correct answer is, -13000 g

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The given expression is:

(9.1\times 10^4)(1.1\times 10^{-5})(\log 10^{-13})(1000)g

As we know that,

\log 10^{-13}=-13

\Rightarrow (9.1\times 10^4)(1.1\times 10^{-5})(-13)(1000)g

\Rightarrow -13013g

True value means, the rounding off the number. So,

\Rightarrow -13000g

Therefore, the correct answer is, -13000 g

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If someone understands this please help
katrin [286]

Answer:

A= 4

B= 4

C= -1

D= 4

E= -1

F= 4

G= -1

Step-by-step explanation:

The expected value equation is the probability of something happening multiplied by the amount of times it happens. In this case you have four equal sized sections, so you have a one in four chance to land in any of these sections. A, B, D, and F represent the four for this one in four chance. C, E, and G represent the amount of points you get when you land on those sections, in this case -1

3 0
3 years ago
A new medical test provides a false positive result for hepatitis 2% of the time that is a perfectly healthy subject being teste
Oxana [17]
Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.

The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02


Part A:

</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:

</span>P(X)={ ^nC_xp^x(1-p)^{n-x}} \\  \\ P(0)={ ^{30}C_0(0.02)^0(1-0.02)^{30-0}} \\  \\ =1(1)(0.98)^{30}=0.5455
<span>

Part B:

The mean of a binomial distribution is given by

</span>\mu=np \\  \\ =30(0.02) \\  \\ =0.6
<span>
The standard deviation is given by:

</span>\sigma=\sqrt{np(1-p)} \\ \\ =\sqrt{30(0.02)(1-0.02)} \\ \\ =\sqrt{30(0.02)(0.98)}=\sqrt{0.588} \\  \\ =0.7668
<span>

Part C:

This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>
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Answer:

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Step-by-step explanation:

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vovangra [49]

Answer:

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Step-by-step explanation:

Let's see if we can think of two numbers that multiply to be 3(-5)=-15

andd add up to be -2

How about -5 and 3? That work's! :)

3y^4-5y^2+3y^2-5

Factor by grouping!

y^2(3y^2-5)+1(3y^2-5)\\(3y^2-5)(y^2+1)

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