Ask question

Ask question

All categories

3 years ago

8

Carter pushes a bag full of basketball jerseys across the gym floor. The he pushes with a constant force of 21 newtons. If he pu

shes the bag 9 meters in 3 seconds, how much power does he use? (Hint: 1 watt = 1 .) A. 3 watts B. 7 watts C. 27 watts D. 63 watts E. 189 watts

2 answers:

N76 [4]3 years ago

5 0

Work = (force) x (distance)

Work = (21 Newtons) x (9 meters) = 189 Joules

Power = (work done) / (time to do the work)

Power = (189 Joules) / (3 sec)

Power = (63 watts/sec)

<em>Power = 63 watts </em>(D)

vovangra [49]3 years ago

4 0

Answer:

DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD

Explanation:

DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD IIIIIIIIIIIIIIISSSSSSSSSSSSSSSSSSS TTTTTTHHHHHHHHEEEEEEEE AAAAAAANSWER

You might be interested in

The amount of gravitational potential energy released as:_________.

nordsb [41]

Answer:

b.it depends on the distance it falls

8 0

3 years ago

Please help calculate them<br> A-f please very urganr

valentina_108 [34]

Three 40w lamp for 6 hours

8 0

3 years ago

A projectile falls beneath the straight-line path it would follow if there were no gravity. How many meters does it fall below t

maria [59]

Answer:

Explanation:

Suppose v is the initial velocity and $\theta$ is the angle of inclination

distance traveled in vertical direction in t=1 s

When gravity is present

$y=vt+\frac{1}{2}at^2$

where $y=vertical\ distance$

$a=acceleration$

$t=time$

$v=initial\ velocity$

here initial velocity is v\sin \theta [/tex] so

$y=v\sin \theta \times 1-\frac{1}{2}gt^2$

$y=v\sin \theta -0.5g$

In absence of gravity

$y_2=v\sin \theta \times t$

$y_2=v\sin \theta \times 1$

$\Delta y=y_2-y=v\sin \theta -v\sin \theta +0.5 g=4.9\ m$

4 0

3 years ago

Part A Determine the magnitude of the x component of F using scalar notation. Fx F x = nothing lb Request Answer Part B Determin

maksim [4K]

As we know that force F makes an angle of 60 degree with X axis

so the X component is given as

$cos60 = \frac{F_x}{F}$

now we have

$F_x = F cos60$

$F_x = 0.50 F$

Similarly we know that force F makes an angle of 45 degree with Y axis

so the X component is given as

$cos45 = \frac{F_y}{F}$

now we have

$F_y = F cos45$

$F_y = 0.707 F$

Now for the component along z axis we know that

$F_x^2 + F_y^2 + F_z^2 = F^2$

now plug in all components

$(0.707 F)^2 + (0.50 F)^2 + F_z^2 = F^2$

$0.5 F^2 + 0.25 F^2 + F_z^2 = F^2$

$F_z^2 = F^2(1 - 0.75)$

$F_z^2 = 0.25 F^2$

$F_z = 0.5 F$

5 0

3 years ago

GaryK [48]

Answer:

3. is made of nucleotides

7 0

3 years ago