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kotykmax [81]
3 years ago
8

What is rhe average velocity od a baseball dropped from rest that falls for 2 seconds?​

Physics
1 answer:
SOVA2 [1]3 years ago
3 0

Answer:

19.6m/s

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 2s

Unknown:

Average velocity  = ?

Solution:

We can use the final velocity of the ball before landing to determines its average velocity ;

 Using;

              v  = u + gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

              v  = 0 + 9.8 x 2 = 19.6m/s

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viktelen [127]
<span>A baseball speeds up as it falls through the air.
Yes.  Forces on the balloon are unbalanced. 
The balloon is speeding up, so we know that the downward force
of gravity is stronger than the upward force of air resistance.

A soccer ball is at rest on the ground.
No. The ball is not accelerating, so we know that the forces on it
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An ice skater glides in a straight line at a constant speed.
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A bumper car hit by another car moves off at an angle.
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5 0
3 years ago
Read 2 more answers
A baseball 0.145kg is thrown vertically upwards with an initial velocity of 20m/s. Use the law of conservation of energy to find
kvasek [131]

Answer: 20.4m

Explanation:

Mass = 0.145kg

Initial velocity, Vi =20m/s

Initial kinetic energy K =1/2mv^2

Initial potential energy Ui = mgx = 0joules

: From conservation of energy,

Uf + Kf = Ui + Ki ( where f represent (final) )

Thus

mgXf + 0 = 0+1/2 mv^2

Xf = Vi^2/ 2g

= (20m/s) ^2/ 2(9.81m/s)^2

=20.4m

5 0
2 years ago
Ok ths is my last one i swear this is for u sheystar
tino4ka555 [31]

Answer:

given below.

Explanation:

a = Indirect

b = Not Indirect

c = Indirect

d = Not Indirect

e = Not Indirect

4 0
2 years ago
An animal cell placed in pure distilled 100% will
jasenka [17]

in a hypotonic solution like distilled water, a red blood cell would burst, because inside the cell has a higher solute concentration than outside.

In a hypertonic solution, there is a higher solute concentration on the outside of the cell than on the inside, causing the cell to shrivel.

i hope this helps

8 0
3 years ago
A 500 kg object is hanging from a spring attached to the ceiling. If the spring constant in the spring is 900 N/kg, how far does
My name is Ann [436]

We are given that a 500 kg object is hanging from a spring. To determine the amount the spring is stretched we will use Hook's law, which states the following:

F=kx

Where:

\begin{gathered} F=\text{ force} \\ k=\text{ spring constant} \\ x=\text{ distance stretched} \end{gathered}

Since the object is hanging the only force acting on the spring is the weight of the object. The weight of the object is:

F_g=mg

Where:

\begin{gathered} m=\text{ mass} \\ g=\text{ acceleration of gravity} \end{gathered}

Plugging in the values we get:

F_g=(500\operatorname{kg})(9.8\frac{m}{s^2})

Solving the operations:

F_g=4900N

Now we solve for "x" from Hook's law by dividing both sides by "k":

\frac{F}{k}=x

Now we plug in the known values:

\frac{4900N}{900\frac{N}{m}}=x

Solving the operations:

5.4m=x

Therefore, the spring is stretched by 5.4 meters.

7 0
11 months ago
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