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kotykmax [81]
3 years ago
8

What is rhe average velocity od a baseball dropped from rest that falls for 2 seconds?​

Physics
1 answer:
SOVA2 [1]3 years ago
3 0

Answer:

19.6m/s

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 2s

Unknown:

Average velocity  = ?

Solution:

We can use the final velocity of the ball before landing to determines its average velocity ;

 Using;

              v  = u + gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

              v  = 0 + 9.8 x 2 = 19.6m/s

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A truck travels to and from a stone quarry that is located 2.5km to the east.
Harrizon [31]

Answer:

Distance is 5.0 km and displacement is 0 km.

Explanation:

The diagram is shown below.

Distance is the total length that the truck covers along the complete journey. The truck moves from a stone quarry covering a length of 2.5 km and then again come back to the same point and thus covering another 2.5 km. Therefore, the total length covered by the truck is the sum of forward and backward paths which is equal to 5.0 km.

Now, displacement depends only on the initial and final position. It is given as the difference of final position and initial position. So, the truck starts from stone quarry and returns back to the same position. So, the initial position and final position is same. Therefore, the difference is 0 and hence displacement is zero.

5 0
3 years ago
The acceleration of gravity is 9.8m/s2. How fast will an object be moving if it falls for three seconds?
Mice21 [21]

Answer:

Acceleration

\frac{distace}{time}

When we cross multiply, distance will be equal to acceleration multiply by time

Distance = acceleration x time

Distance = 9.8 x 3

= 29.4 m/s

7 0
2 years ago
A block weighing 35 N is resting on a steel table (us = 0.40).
rosijanka [135]

Answer: 14

Explanation:

Force(normal)*coefficient

4 0
3 years ago
A 25N force is applied to a bar that can pivot around its end. The force is r=0.75 m away from the end of an angle at 0= 45. wha
andrew-mc [135]

Answer:

The answer is B. I had a question like this last week in my physics practice exam. dont have alot of time so I cant explain right now

Explanation:

8 0
3 years ago
10 points) A rubber ball and a lump of putty of the same mass m = 0.05 kg are thrown with the same speed v=10.0 m/s in positive
snow_lady [41]

Answer:

the ball experiences the greater momentum change

Explanation:

You have to take into account that momentum change is given by

\Delta p=mv_f-mv_b

where vf and vb are the speed of the object after and before the impact.

In the case of the ball you have

\Delta p=(0.05kg)(-10.0\frac{m}{s})-(0.05kg)(10.0\frac{m}{s})=-1kg\frac{m}{s}

where the minus of vf is included due to the motion is in an opposite direction regarding with vb

And for the lump

\Delta p=(0.05kg)(10.0\frac{m}{s})-(0.05kg)(0\frac{m}{s})=0.5kg\frac{m}{s}

Hence, the ball experiences the greater change

hope this helps!!

4 0
3 years ago
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