Answer:
Step-by-step explanation:
given a point 
the equation of a line with slope m that passes through the given point is
or equivalently
.
Recall that a line of the form 
, the y intercept is b and the x intercept is 
.
So, in our case, the y intercept is 
and the x intercept is 
.
In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph 
. Which means that 
The slope of the tangent line is given by the derivative of the function evaluated at 
. Using the properties of derivatives, we get
. So evaluated at we get 
Replacing the values in our previous findings we get that the y intercept is
The x intercept is
The triangle in consideration has height 
and base 
. So the area is
So regardless of the point we take on the graph, the area of the triangle is always 2.
44 sq inches, i am so not sure.
Answer:
x = 11, -1
Step-by-step explanation:
First, let's identify what the quadratic formula is:
x = [-b ± √(b² - 4(a)(c))] / 2
Our equation is written in standard form:
ax² + bx + c = 0
x² - 10x - 11 = 0
Let's plug in what we know.
x = [-(-10) ± √((-10)² - 4(1)(-11))] / 2
Evaluate the exponent.
x = [-(-10) ± √(100 - 4(1)(-11))] / 2
Simplify the negatives.
x = [10 ± √(100 - 4(1)(-11))] / 2
Multiply.
x = [10 ± √(100 + 44)] / 2
Simplify the parentheses.
x = [10 ± √(144)] / 2
Simplify the radical (√)
x = [10 ± 12] / 2
Evaluate the ±.
x = [10 + 12] / 2
x = [22] / 2
x = 11
or
x = [10 - 12] / 2
x = [-2] / 2
x = -1
Your answers are x = 11, -1
Hope this helps!
The answer would be 3n - 8
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