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3 years ago

What is usually the best way to display data if you have more than 10 results?

Mathematics

1 answer:

mestny [16]3 years ago

5 0

Answer:

Probably on a pie chart.

Step-by-step explanation:

You can color code each piece of data, and show the percentage for each on the pie chart.

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What is the slope intercpet form of a line that goes through (-1,2) and (0,3)

Nana76 [90]

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3 years ago

What is the domain and range of 4n/n-5 -2?

nlexa [21]

Answer:

Domain: (-∞, 5)∪ (5, ∞)

Range: (-∞, 2)∪ (2, ∞)

7 0

3 years ago

Read 2 more answers

The coordinates of the vertices of a triangle are (−3,2), (0,−3), and (−4,−2).

sergeinik [125]

The perimeter of the triangle, rounded to the nearest tenth, is 8.5 units.

6 0

3 years ago

4x - 5y = 15 find the slope and y-intercept

Mazyrski [523]

Answer:

slope=4/5

y-intercept = -3

Step-by-step explanation:

first we need to rewrite the expression to

$y=mx+b$

were b is the y-intercept and m the slope

$4x-5y=15\\\\4x-5y+5y=15+5y\\\\4x+0=15+5y\\\\4x=5(3)+5(y)\\\\4x=5(3+y)\\\\\frac{1}{5}*4x= \frac{1}{5}*5(3+y) \\\\\frac{4x}{5}=3+y\\\\\frac{4x}{5} -3=3+y-3\\\\\frac{4x}{5} -3=y+0\\\\y=\frac{4x}{5} -3\\\\y=\frac{4}{5}x-3$

so there we have it

$m=\frac{4}{5} \\\\b=-3$

6 0

4 years ago

A manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly.

denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let $\mu$ = population mean light bulb life.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 500 hours {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, $H_A$ : $\mu$ < 500 hours {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean bulb life = 490 hours

σ = population standard deviation = 50 hours

n = sample of light bulbs = 100

So, the test statistics = $\frac{490-500}{\frac{50}{\sqrt{100} } }$

= -2

The value of z test statistics is -2.

Now, at 0.01 significance level the z table gives critical value of -2.33 for left-tailed test.

Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

7 0

3 years ago