To form a hydrogen bond, what must the non-hydrogen atom ( N , O , or F ) involved in the bond possess?
2 answers:
Explanation:
As atomic number of hydrogen is 1. So, it needs to gain one electron from a donor atom in order to become stable in nature.
Therefore, when a hydrogen bond is formed with a non-hydrogen atom then there must be presence of a non-bonding electron.
For example, atomic number of nitrogen atom is 7 and its electronic distribution is 2, 5.
Here, three electrons are needed by a nitrogen atom. And, when three nitrogen atoms get attached to a nitrogen atom then a compound is formed.
Thus, we can conclude that to form a hydrogen bond, the non-hydrogen atom ( N , O , or F ) involved in the bond must possess a non-bonding electron pair.
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Explanation:
Oxidation reduction reactions are the reactions in which one specie oxidizes and other reduces.
For example,
This is a oxidation reduction reaction because sodium in elemental state ( 0 oxidation state) oxidizes to Na⁺ in NaCl. Also H⁺ in HCl reduces to H° in H₂.
Elements are present in 0 oxidation state and either it is formed or consumed, its oxidation state has to be changed for a chemical reaction to occur. Hence, it is true.