Answer:
A
Explanation:
Developing work ethics won't lower your stress although it may make your conscience a little happier. Not B
Not C. Procrastinating just makes things harder. The mountain of things to do is not diminishing at all and your stress knows it.
Not D. Although D is the second best answer, setting goals is not really an action. It is a plan for how to work. But it is not work. Still having a goal is useful.
The answer is A. Just keep hitting what you have to do at a steady pace.
Answer : The current passing between the electrodes is, 
Explanation :
First we have to calculate the charge of sodium ion.
where,
q = charge of sodium ion
n = number of sodium ion = 
e = charge on electron = 
Now put all the given values in the above formula, we get:
Now we have to calculate the charge of chlorine ion.
where,
q' = charge of chlorine ion
n = number of chlorine ion = 
e = charge on electron =
Now put all the given values in the above formula, we get:
Now we have to calculate the current passing between the electrodes.
Thus, the current passing between the electrodes is,
Answer:
35Cl = 75.9 %
37Cl = 24.1 %
Explanation:
Step 1: Data given
The relative atomic mass of Chlorine = 35.45 amu
Mass of the isotopes:
35Cl = 34.96885269 amu
37Cl = 36.96590258 amu
Step 2: Calculate percentage abundance
35.45 = x*34.96885269 + y*36.96590258
x+y = 1 x = 1-y
35.45 = (1-y)*34.96885269 + y*36.96590258
35.45 = 34.96885269 - 34.96885269y +36.96590258y
0.48114731 = 1,99704989y
y = 0.241 = 24.1 %
35Cl = 34.96885269 amu = 75.9 %
37Cl = 36.96590258 amu = 24.1 %
Answer:
The products are Calcium oxide and Carbon dioxide.
Explanation:
When calcium carbonate is heated, thermal decomposition occurs.
Calcium calcium → Calcium oxide + Carbon dioxide
Answer:
Zn =⇒ Zn+2(0.10) + 2e- (anode)
Zn+2(?M) + 2e- === Zn(s) (cathode)
Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn
E = E^o -0.0592 log Q; in this case E^o is zero.
E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2
23 mV x 1 volt/1000mv = 0.023 Volts
0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
0.023 = -0.0296 { log 0.10 – log [Zn+2] }
0.023 = -0.0296{ -1 - log[Zn+2] }
0.023 = +0.0296 + 0.0296log[Zn+2]
-0.0066 = 0.0296log[Zn+2]
-0.22= log[Zn+2]
[Zn+2] = 10^-0.22 = 0.603 Molar
