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3 years ago

If you produced 76.10 grams of potassium chloride in the reaction how many grams of potassium were required?

Chemistry

1 answer:

11111nata11111 [884]3 years ago

6 0

Answer:39.8375

Explanation:

The mole for the equation is 1:1

Then the molar mass of KCl is 74.5g

Molar mass of k is 39

74.5g of KCl gives 39g of k

76.10g of KCl gives xg of k

X= 76.10×39/74.5

X= 2967.9/7

X= 39.8375

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1.8 mol HCl and 3.3 mol NaOH react accord- ing to the equation HCl + NaOH −→ NaCl + H2O . Calculate the amount in moles of NaCl

ollegr [7]

Answer:

1.8 moles of NaCl must be produced.

Explanation:

Based on the reaction:

HCl + NaOH → NaCl + H2O

1 mol of HCl reacts with 1 mol of NaOH to produce 1mol of NaCl

To solve this question we must find, as first, the limiting reactant:

1.8 moles of HCl will need 1.8 moles of NaOH for a complete reaction (Ratio of reaction 1:1). As there are 3.3 moles of NaOH,

HCl is limiting reactant

When the 1.8 moles of HCl react completely,

1.8 moles of NaCl must be produced because 1 mole of HCl produce 1 mole of NaCl

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3 years ago

Why is Galileo Galilei impotant?

Rainbow [258]

Answer:

He provided a number of scientific insights that laid the foundation for future scientists. He also improved telescope that helped further the understanding of the world and universe.

Explanation:

5 0

3 years ago

Read 2 more answers

What is the mass of 5 mole of ammonia . Calculate the number of NH₃ molecules, nitrogen atom and hydrogen atoms in it..

Aloiza [94]

Molar mass of NH_3

$\\ \sf\longmapsto 14u+3(1u)$

$\\ \sf\longmapsto 14u+3u$

$\\ \sf\longmapsto 17g/mol$

We know.

No of moles=Given mass/Molar mass

$\\ \sf\longmapsto Given\;Mass=17(5)$

$\\ \sf\longmapsto Given \:Mass\:of\:NH_3=85g$

Now

Lets write the balanced equation

$\\ \sf\longmapsto N_2+3H_2=2NH_3$

There is 2moles of Ammonia
3moles of H_2
1mole of N_2

Now

$\boxed{\sf No\:of\:Molecules =No\:of\;moles\times Avagadro\:no}$

For Hydrogen

$\\ \sf\longmapsto 3\times 6.023\times 10^{23}$

$\\ \sf\longmapsto 18.069\times 10^{23}$

$\\ \sf\longmapsto 1.8\times 10^{22}molecules$

For Ammonia

$\\ \sf\longmapsto 2\times 6.023\times 10^{23}$

$\\ \sf\longmapsto 12.046\times 10^{23}$

$\\ \sf\longmapsto 1.2\times 10^{22}molecules$

For Nitrogen

$\\ \sf\longmapsto 1\times 6.023\times 10^{23}$

$\\ \sf\longmapsto 6.023\times 10^{23}molecules$

3 0

3 years ago

Which two elements are most abundant within the sun?

padilas [110]

Hydrogen and helium.

3 0

3 years ago

What type of bond is this combination likely to form

kari74 [83]

Answer:

A combination is certainly possible, but you should not take formal charges so literally

Normally, when a covalent bond is found, the two atoms both bring in one electron. As you identify correctly, in the case of nitric acid that would not be possible completely. If you draw the different possible resonance structures, the most likely structure has a single bond between the nitrogen and an oxygen where the oxygen has 3 lone pairs and both electrons in the bond are donated by the nitrogen. This makes the nitrogen "positive" and that oxygen "negative", but in fact the electrons move more freely in the molecule and charges are more distributed. You will not be able to find "the negatively charged" oxygen atom.

Explanation:

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4 0

3 years ago