Given two points

and

The distance between them is >>>
![D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%5B%5D%7B%28y_2-y_1%29%5E2%2B%28x_2-x_1%29%5E2%7D)
The points given are (Sqrt(20), Sqrt(50)) and (Sqrt(125), Sqrt(8)), so their distance is >>>
![\begin{gathered} D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ D=\sqrt[]{(\sqrt[]{8}-\sqrt[]{50})^2+(\sqrt[]{125}-\sqrt[]{20})^2} \\ D=\sqrt[]{(\sqrt8)^2-2(\sqrt[]{8})(\sqrt[]{50})+(\sqrt[]{50})^2^{}+(\sqrt[]{125})^2-2(\sqrt[]{125})(\sqrt[]{20})+(\sqrt[]{20})^2} \\ D=\sqrt[]{8-2(2\sqrt[]{2})(5\sqrt[]{2})+50+125-2(5\sqrt[]{5})(2\sqrt[]{5})+20} \\ D=\sqrt[]{8-40+50+125-100+20} \\ D=\sqrt[]{63} \\ D=3\sqrt[]{7} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%28y_2-y_1%29%5E2%2B%28x_2-x_1%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%28%5Csqrt%5B%5D%7B8%7D-%5Csqrt%5B%5D%7B50%7D%29%5E2%2B%28%5Csqrt%5B%5D%7B125%7D-%5Csqrt%5B%5D%7B20%7D%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%28%5Csqrt8%29%5E2-2%28%5Csqrt%5B%5D%7B8%7D%29%28%5Csqrt%5B%5D%7B50%7D%29%2B%28%5Csqrt%5B%5D%7B50%7D%29%5E2%5E%7B%7D%2B%28%5Csqrt%5B%5D%7B125%7D%29%5E2-2%28%5Csqrt%5B%5D%7B125%7D%29%28%5Csqrt%5B%5D%7B20%7D%29%2B%28%5Csqrt%5B%5D%7B20%7D%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B8-2%282%5Csqrt%5B%5D%7B2%7D%29%285%5Csqrt%5B%5D%7B2%7D%29%2B50%2B125-2%285%5Csqrt%5B%5D%7B5%7D%29%282%5Csqrt%5B%5D%7B5%7D%29%2B20%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B8-40%2B50%2B125-100%2B20%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B63%7D%20%5C%5C%20D%3D3%5Csqrt%5B%5D%7B7%7D%20%5Cend%7Bgathered%7D)
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The midpoint formula is >>>

Plugging in the points, we have >>>
Answer: 211 miles
Step-by-step explanation: An equation for this could be:
base fee + additional charge (miles driven) = total charge
19.99 + 0.86(x) = 201.45
0.86(x) = 201.45 - 19.99
0.86(x) = 181.46
x =
= <em>211 miles</em>
Answer:
1. 3/4, 0.75, 75%
2. 1/4, 0.25, 25%
3. 3/5, 0.6, 60%
4. 5/5, 1, 100%
5. 1/2, 0.5, 50%
6. 4/6, 0.6, 66.6%
Step-by-step explanation:
It’s A) 9.1 because it equals 82.81 while answer B) 9.2 equals 84.64.
Add another triangle to make it a square/rectangle. Then find the perimeter of that. Then divide the answer by 2. That will be the perimeter of the shape.