Answer:
idk
Step-by-step explanation:
Answer:
Height: 3/2 inches
Length: 12 inches
Width: 4 inches
Step-by-step explanation:
Let x is the side length of the square
The height of the box by cutting squares off :x
- The new length of the cardboard = 15 -2x (because we cut from 4 corners)
- The new width of the cardboard = 7 -2x (because we cut from 4 corners)
The new volume of it is:
V = (15 -2x) (7 -2x) x
<=> V =
To maximum volume, we use the first derivative of the volume
<=> 
<=> 
<=> 2x -3 = 0 or 6x -35 = 0
<=> x = 3/2 or x = 35/6
To determine which value of x gives a maximum, we evaluate
= 24x -88
= 24(3/2) -88 = -52
= 24(35/6) -88 = 52
We choose x = 3/2 to have the maximum volume because the value of x that gives a negative value is maximum.
So the dimensions (in inches) of the box is:
Height: 3/2 inches
Length: 15-2(3/2) = 12 inches
Width: 7 - 2(3/2) = 4 inches
Just draw a graph and plot them on the graph then count how many squares (in short) there is between them.
Answer:
solution set is (x,y) = (7,6)
Step-by-step explanation:
solving by substitution method
2x +y=20--------------1
6x-5y=12---------------2
from equation 1, solve for y
2x+y=20
y= 20-2x------equation 3
adding value of y in equation 2
6x-5y=12
6x-5(20-2x)=12
6x-100+10x=12
16x= 12+100
16x= 112
x= 112/16
x=7
adding value of x in equation 3
y= 20-2x
y= 20- 2(7)
y=20-14
y=6
so solution set (x,y) = (7,6)
Answer:
10^-3
Step-by-step explanation: