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aleksklad [387]
3 years ago
11

Math question help me

Mathematics
1 answer:
lbvjy [14]3 years ago
3 0
Can’t see the picture can you post it again? Can only see 97^7/6b^3
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Y+5=2(x+1) ordered pairs
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(0,-3) (1, -1) (2, 1) ....
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if ( in one month ) I make a total of 15 calls at standard hours, what is the difference in cost between the two contracts ? ans
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5 0
3 years ago
For what value of x does (x + 3)^2-5=0
ArbitrLikvidat [17]

Answer:

x = -3±sqrt( 5)

Step-by-step explanation:

(x + 3)^2-5=0

Add 5 to each side

(x + 3)^2-5+5=0+5

(x + 3)^2 = 5

Take the square root of each side

sqrt((x + 3)^2 )=±sqrt( 5)

x+3 = ±sqrt( 5)

Subtract 3 from each side

x+3-3 = -3±sqrt( 5)

x = -3±sqrt( 5)

7 0
3 years ago
!!!!Please help!!! I am dying!!
stellarik [79]

Answer:

Therefore (x,y)=(3,7)

Step-by-step explanation:

put the second equation into the first

x+4=3x-2

x-3x=-2-4

-2x=-6

x=3

plug x=3 into the second equation

y=3+4=7

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1 year ago
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0,1 chance is the correct answer

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