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Maru [420]
2 years ago
8

Your class is having a pizza party. You buy 5 pizzas Each pizz has 4 slices. How many slices is that altogether?​

Mathematics
2 answers:
Vesna [10]2 years ago
4 0

Answer: 20 slices of pizza

Step-by-step explanation:

you multiply 5 times 4

bixtya [17]2 years ago
3 0

Answer:

20

Step-by-step explanation:

5 x 4 = 20

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Given that lines a and b are parallel, what angles formed on line b when cut by the transversal are congruent with ∠2?
Kruka [31]

Answer:

The angles formed on line b when cut by the transversal are congruent with ∠2 are \angle{6}\text{ and }\angle{7}

Step-by-step explanation:

Consider the provided information.

If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .

The angles on the same corners are called corresponding angle.

Alternate Angles:  Angles that are in opposite positions relative to a transversal intersecting two lines.

∠2 and ∠6 are corresponding angles

Therefore, ∠2 = ∠6

∠2 and ∠7 are alternate exterior angles

Therefore, ∠2 = ∠7

Hence, the angles formed on line b when cut by the transversal are congruent with ∠2 are \angle{6}\text{ and }\angle{7}

3 0
3 years ago
Q16. Find x^2 + 1/x^2 , if x + 1/x = 3
erica [24]

Answer:

2 \times  x \times \frac{1}{x}  =  2 \\  {x}^{2}   +  {y }^{2}  + 2xy =  {(x + y)}^{2} \\ {x}^{2}  +  \frac{1}{ {x}^{2} }  + 2 = {(x +  \frac{1}{x} })^{2}  =  {3}^{2}  = 9

8 0
2 years ago
Two friends sold many pieces of furniture and made ​$1550 during their garage sale. They had fifteen more​ $10 bills than​ $50 b
Novosadov [1.4K]

Answer:

The number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

Step-by-step explanation:

Let n₁ = number of $ 10 bills,

Let n₂ = number of $ 20 bills and

Let n₃ = number of $ 50 bills

Given that 10n₁ + 20n₂ + 50n₃ = 1550    (1)

Also, since we have fifteen more​ $10 bills than​ $50 bills, n₁ = n₃ + 15  (2)

and we have 4 more than three times as many​ $20 bills as​ $50 bills. n₃ = 3n₂ + 4. (3)

substituting equations (2) and (3) into (1), we have

10(n₃ + 15) + 20n₂ + 50n₃ = 1550

expanding the bracket, we have

10n₃ + 150 + 20n₂ + 50n₃ = 1550

collecting like terms, we have

60n₃ + 150 + 20n₂ = 1550

inserting equation (3), we have

60(3n₂ + 4) + 150 + 20n₂ = 1550

expanding the bracket, we have

180n₂ + 240 + 150 + 20n₂ = 1550

collecting like terms, we have

200n₂ + 390 = 1550

subtracting 390 from both sides, we have

200n₂ = 1550 - 390

200n₂ = 1160

dividing both sides by 200, we have

n₂ = 1160/200

n₂ = 5.8

n₂ ≅ 6 since it cannot be a fraction.

Substituting this into (3), we have

n₃ = 3n₂ + 4 = 3(6) + 4 = 18 + 4 = 22

substituting n₃ into (2), we have

n₁ = n₃ + 15 = 22 + 15 = 37

So, the number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

3 0
3 years ago
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