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3 years ago

It part of a Law of Exponents

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

4 0

I think its c but im not sure??

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Graph the line with slope<br> −1/2<br> and y-intercept 3.

joja [24]

Step-by-step explanation:

m=-1/2

b(0,3)

mark (0,3)then go down 1 and 2 to the right as in positive side

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3 years ago

What is 121,580 rounded to the nearest thousand?

AfilCa [17]

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7 0

3 years ago

Read 2 more answers

A baseball team's total wins and losses for one season is 162. The number of wins is 6 less than 2 times the number of losses. W

aivan3 [116]

Answer:

x + y = 162 and x = 2y - 6

Step-by-step explanation:

Let the total wins be x

Let the total loss be y

If a baseball team's total wins and losses for one season is 162, this can be expressed as;

x + y = 162 ....... 1

If the number of wins is 6 less than 2 times the number of losses, this is expressed as;

2 times the number of losses = 2y

6 less than 2 times the number of losses = 2y - 6

Now, If the number of wins is 6 less than 2 times the number of losses this is expressed as;

x = 2y - 6 .... 2

Hence the required system of equation are;

x + y = 162 and x = 2y - 6

8 0

2 years ago

I can’t seem to find the answer but the closest I have gotten was D . Do anyone know?

hichkok12 [17]

The correct answer is c (x-1)^2=8

4 0

3 years ago

Really need help guys!<br> Love you if you can solve them wiz steps!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

$x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\$

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

$b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}$

$c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16$

$d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6$

5 0

1 year ago